Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- 1. Calculate the following properties for the data provided in the Table below for a coarse aggregate sample. a. Bulk SSD specific gravity b. Bulk Dry specific gravity A Bulk Dry Sp. Gr. = c. Apparent specific gravity d. Absorption capacity. В — С B Bulk SSD Sp. Gr. = В — С where A Apparent Sp. Gr. = А — С A = dry weight B = SSD weight C = submerged weight В — А (100) A Absorption (%) Weight of Pan + Oven- Dry Aggregate Weight of Pan Weight of Submerged Aggregate Weight of Pan + SD Aggregate 0.8495 Ib 1.9885 lb 0.6870 lb 1.9630 Ib 2. If the Moisture Content of a stockpile sample of the same coarse aggregates is 1.85 %, what is the moisture state of aggregate sample? Select from the four standard moisture states. Explain how you arrived at the answer. 3. If Bulk unit weight of coarse aggerates is 98 Ib/ft³determine the % Voids of dry-rodded aggregate. Youlk S.G(Bulk Dry)*Pwater %Solids * 100 4. Determine the % solids for 2 cases discussed in pre-lab video by using below data.…arrow_forwardA 1g granular powder have the following data below, compute for the following: Volume of the solid alone = 1 cm3/g Volume of intraparticle pores = 0.2 cm3/2g Volume of spaces between particle = 3.2 cm3/g Volume after tapping = 2.4 cm3/2g Note: Answer should be in three decimal places A) Specific volume = ? cm3/g B) Specific granule volume = ? cm3/g C) Specific bulk volume = ? cm3/g D) Total porosity = ? E) Interspace porosity = ? F) Intraparticle porosity = ? G) Hausner ratio = ? H) Carr's compressibility index = ?arrow_forwardReferring to the aggregate gradations A, B, and C in Figure P5.26, answer the following questions: a. What is the maximum size of each gradation? b. What is the nominal maximum size of each gradation? c. Classify each gradation as dense, open, or gap indicating the reason for each classification. 100 A 80- 60 40 0.075 0.30 1.18 2.36 4.75 9.5 12.5 19.0 25.0 0.15 0.60 Sieve sizes (mm) FIGURE P5.26 Percent passing 20arrow_forward
- Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket =14L Weight of empty bucket = 9.21kg Weight of bucket filled with dry rodded coarse aggregate: Trial 1 =34,75 kg Trial 2 =34.06 kg Trial 3 =35.74 kg a. Calculate the average dry-rodded unit weight b.If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.arrow_forwardhelp find a, and barrow_forward“construction of gravity-driven oil and water emulsion separator system in sinks using zeolite” Answer both • Significance of the research in local setting • edge of the product from other productarrow_forward
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