Analyze and determine the outputs of the following program statements: #include #include int main() { float a=3, c=4, *p,*q; int i,j,k,n=3, b=3,w-2; float x[3][4]={9,8,1,2,3,4,5,6,7,8,9,10}, z[4][3]; float y[4]={1,2,3,4}; for(i=0;i<4;i++) { for (j-0;j<3;j++) z[j][i]=x[i][j]; z[2][1]=x[2][1]; q=&z[2][1]; printf("*q= %.2f\n", *q*2); for(i=0;i<3;++i) { c+=y[i]-1; a+=y[i]+b; p+=i; printf("a=%0.2f\n c=%@.2f\n z[2][1]=%@.2f \n",a,c,z[2][1]); i=4;j=3;k=Dn-13; if (i!=j*j-3) {i=k;j=j+i;} else if(i<8) {w=n+i+j+1+y[j]]; w=n+a+k+2+y[i];} if(w<10) {p=&n; printf("w=%d",w+5); else { printf("w=%d\n",w-5);}

C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter7: Arrays
Section7.3: Declaring And Processing Two-dimensional Arrays
Problem 1E: (Practice) Write specification statements for the following: a. An array of integers with 6 rows and...
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Analyze and determine the outputs of the following program statements:
#include <stdio.h>
#include <math.h>
int main()
{
float a=3, c=4,*p,*q;
int i,j,k,n=3, b=3,w-2;
float x[3][4]={9,8,1,2,3,4,5,6,7,8,9,10}, z[4][3];
float y[4]={1,2,3,4};
for (i=0;i<4;i++)
{
{ for (j=0;j<3;j++)
z[j][i]=x[i][j];
}
z[2][1]=x[2][1];
q=&z[2][1];
printf("*q= %.2f\n", *q*2);
for(i=0;i<3;++i)
{ C+=y[i]-1;
a+=y[i]+b;
p+=i;
}
printf("a=%0.2f\n c=%0.2f\n z[2][1]=%0.2f \n", a,c,z[2][1]);
i=4;j=3;k=n-1;
if (i!=j*j-3)
{i=k;j=j+i;}
else if(i<8)
{w=n+i+j+1+y[j]; w=n+a+k+2+y[i];}
if(w<10)
{p=&n;
printf("w=%d", w+5);
else
{
printf("w=%d\n",w-5);}
}
Transcribed Image Text:Analyze and determine the outputs of the following program statements: #include <stdio.h> #include <math.h> int main() { float a=3, c=4,*p,*q; int i,j,k,n=3, b=3,w-2; float x[3][4]={9,8,1,2,3,4,5,6,7,8,9,10}, z[4][3]; float y[4]={1,2,3,4}; for (i=0;i<4;i++) { { for (j=0;j<3;j++) z[j][i]=x[i][j]; } z[2][1]=x[2][1]; q=&z[2][1]; printf("*q= %.2f\n", *q*2); for(i=0;i<3;++i) { C+=y[i]-1; a+=y[i]+b; p+=i; } printf("a=%0.2f\n c=%0.2f\n z[2][1]=%0.2f \n", a,c,z[2][1]); i=4;j=3;k=n-1; if (i!=j*j-3) {i=k;j=j+i;} else if(i<8) {w=n+i+j+1+y[j]; w=n+a+k+2+y[i];} if(w<10) {p=&n; printf("w=%d", w+5); else { printf("w=%d\n",w-5);} }
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