na survey of 2074 adults in a recent year, 744 made a New Year's resolution to eat healthier. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the The 90% confidence interval for the population proportion p is ( D. Round to three decimal places as needed.)

Which type of confidence interval should you use in this situation? A sample of 400 racing cars showed that 80 cars cost over $700,000. Find the 99% confidence interval of the true proportion of racing cars costing over $700,000.   Question 3 options:   1)  a confidence interval for the mean using a table value from the standard normal distribution.   2)  a confidence interval for the mean using a table value from the t distribution.   3)  a confidence interval for a proportion using a table value from the standard normal distribution.   4)  a confidence interval for proportion using a table value from the t distribution.   5)  none of the above.

In a survey of 3463 adults, 1498 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is ( D. (Round to three decimal places as needed.)

If n = 180 and X = 144, construct a 99% confidence interval for the population proportion, p. Give your answers to three decimals < p <