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- Mendelian Genetics The presence of a dimple on the cheek is governed by a dominant gene. A couple had already 4 children with dimpled cheeks. What would be the probability of having the next child as another dimpled if both parents are heterozygous for this character? Show your solution using Punnett SquareHelp meWhat phenotypes in what ratio would be expected in the F2 generation of the cross with the following information: The genotype of homozygous black, long haired rabbit is BBhh The genotype of homozygous brown, short haired rabbit is bbHH The gamete of homozygous black, long haired rabbit is Bh The gamete of homozygous brown, short haired rabbit is bH F1 progeny is BbHh (heterozygous black, short haired rabbit)
- ybrid Cross - Parental (P) vill be observing the F, offspring of the cross shown in nage. The purple colof (P) of the kernel is the result of ment called anthocyanin, which is dominant and not nked. /hat are the genotypes of the F, offspring if both nts shown are homozygous? F1 Mendel's dihybrid cross always showed a the same ratio ONLY for traits that are not linked on the same mosome and inherited together. If the genes are linked the ratio will not follow Mendel's dihybrid ratio. What is atio seen in dihybrid crosses that are not linked? F2 EXPERIMENTAL QUESTION: Are the genes for color (P) and shape (R) linked (on the same chromosome)?Three genes in fruit flies affect a particular trait, andone dominant allele of each gene is necessary to get awild-type phenotype.a. What phenotypic ratios would you predict amongthe progeny if you crossed triply heterozygous flies?b. You cross a particular wild-type male in successionwith three tester strains. In the cross with one testerstrain (AA bb cc), only 1/4 of the progeny are wildtype. In the crosses involving the other two testerstrains (aa BB cc and aa bb CC), half of the progeny are wild type. What is the genotype of thewild-type male?The accompanying pedigree shows a very unusual inheritance pattern that actually did exist. All progeny areshown, but the fathers in each mating have been omittedto draw attention to the remarkable pattern.a. Concisely state exactly what is unusual about thispedigree.b. Can the pattern be explained by Mendelianinheritance?
- To figure out the outcome of a cross, set up a Punnett square.a. Put the gametes of one parent at the top and those of theother on the left. To determine the allele(s) in each gamete fora given genotype, set up a systematic way to list all the possibilities. (Remember, each gamete has one allele of each gene.)Note that there are 2npossible types of gametes, where n is thenumber of gene loci that are heterozygous. For example, anindividual with genotype AaBbCc would produce 23 = 8 typesof gametes. Write the genotypes of the gametes in circlesabove the columns and to the left of the rows.b. Fill in the Punnett square as if each possible sperm werefertilizing each possible egg, making all of the possibleoffspring. In a cross of AaBbCc * AaBbCc, for example, thePunnett square would have 8 columns and 8 rows, so thereare 64 different offspring; you would know the genotype ofeach and thus the phenotype. Count genotypes and phenotypes to obtain the genotypic and phenotypic ratios. Becausethe…We have crossed true-breeding flies today. Wild type to mutant. Their phenotypes were wt and vg se. (Let’s not worry about males and females for now, just assume both genes are autosomal, which is normal in a Mendelian experiment). The results of a cross are phenotypes. I will be asking you for numbers or a ratio of phenotype numbers you expect to see in the offspring from this cross. To answer this, you’ll need to start with the genotypes of parents, then write their gametes, then write the offspring genotypes, then get the phenotypes based on them. Predict the results of this cross: In case both mutations are recessive; In case both mutations are dominant; In case vestigial wings are recessive and the sepia eyes are dominant.Two plants in a cross were each heterozygous for two gene pairs (AB /ab) whose loci are linked and 30 map units (mu) apart. (Recall that 1 mu is equal to 1% recombination between two genes.) Assuming that crossing over occurs during the formation of both male and female gametes and that the A and B alleles are dominant, determine the phenotypic ratio of their offspring. Part E: What proportion of the offspring of two plants (both (AB/ab ) will be A - B- if the genes are 30 mu apart? Part F: What proportion of the offspring of two plants (both (AB/ab)) will be A - bb if the genes are 30 mu apart? Part G: What proportion of the offspring of two plants (both (AB/ab)) will be aaB- If the genes are 30 mu apart? Part H: What proportion of the offspring of two plants (both (AB/ab)) will be aabb if the genes are 30 mu apart?
- Mendel crossed wrinkle-seeded (rr) plants with pure round-seeded plants (RR). What percentage of the resulting generation had wrinkled seeds?Incomplete dominanceIn Mendel's experiments, if the gene for tall (T) plants was incompletely dominant overthe gene for short (t) plants, what would be the result of crossing two Tt plants? Explain result.This pedigree (Pedigree #2) illustrates the inheritance of a simple Mendelian trait. If individuals III- 5 and III-6 have children, what are the chances that the children would have this disorder? 0% 1/4 2/3 O 1/6 ㅇㅁ