n the hypothesis test? e significance level of a=0.01, so oportion for those under 25. an appropriate confidence interval. the null hypothesis. There is evidence to support the claim that the proportion of people over 55 who as needed.) n the confidence interval? 0, it appears that the two proportions are Because the confidence interval limits include values, it app limits o dream in black and white is the proportion for those under 25. is that those over the age of 55 grew up exposed to media that was displayed in black and white. Can theso results be used to verify that explanation? 0, it appears that the two proportions are Because the confidence interval limits include in black and white is the proportion for those under 25. hose over the age of 55 grew up exposed to media that was displayed in black and white. Can these results be used to verify that e blo difference hetween the proportions of people over 55 and under 25 who dream in black and white, but the results cannot be use

Which of the following is not a condition that needs to be met to develop a confidence interval for a proportion? Multiple Choice The trials are dependent. The values of nt and n1 m) are both greater than or equal to 5. The sample data are the number of successes in n trials. & The probability of a success remains the same from one trial to the next.

You are interested in finding a 99% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 12 randomly selected non-residential college students. Round answers to 3 decimal places where possible.   18 20 20 24 5 28 10 13 5 24 11 11   b. With 99% confidence the population mean commute for non-residential college students is between     ?      and      ?  miles. c. If many groups of 12 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About    ?    percent of these confidence intervals will contain the true population mean number of commute miles and about  ?   percent will not contain the true population mean number of  commute miles.

Domestic cats kill many more wild birds in the United States than scientists thought,” states a recent article.1 Researchers used a sample of n = 140 households in the US with cats to estimate that 35% of household cats in the US hunt outdoors.a. Find a 99% confidence interval for the proportion of household cats in the US that hunt outdoors using this sample information. Show work/calculations used to find SE, ME and confidence interval to full receive credit.Round your answers to three decimal places.b. Interpret your 95% confidence interval in a complete sentence. Use correct units and context.c. Is it plausible that the proportion of household cats in the US hunting outdoors is 0.45? Briefly explain why or why not?

We constructed a 95% confidence interval for a population mean. Which of the following would cause the confidence interval to become wider. Select all that apply. This question does not break the honor code and is not graded. Just practice on topics

A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol levels for 27 patients were recorded before administering the drug and after. The 99% confidence interval for the true mean difference in total cholesterol levels (after - before) was (-78.82, -31.18). Which of the following is the appropriate conclusion?   Question 4 options:   1)  We are 99% confident that the average difference in cholesterol levels is positive, with the higher cholesterol levels being before the drug regimen.   2)  We are 99% confident that the average difference in cholesterol levels is positive, with the higher cholesterol levels being after the drug regimen.   3)  We are 99% confident that the average difference in cholesterol levels is negative, with the higher cholesterol levels being before the drug regimen.   4)  We are 99% confident that the average difference in…

help pleasee! An SRS of n=80 finds 16 smokers. We want to test whether the national smoking prevalence (i.e., the population proportion) is significantly difference than 0.25 at 95% confidence level. Assume that we can use a z-test. What is the standard error of ?̂  under Null Hypothesis? answer choices 0.045 0.048 0.43 0.4

A psychiatrist is interested in finding a 98% confidence interval for the tics per hour exhibited by children with Tourette syndrome. The data below show the tics in an observed hour for 11 randomly selected children with Tourette syndrome. Round your decimal 3 places. 1,12,11,6,10,1,4,7,8,1,9  With 98% confidence the population mean number of tics per hour that children with Tourette syndrome exhibit is between ____ and ____  If many groups of 11 randomly selected  children with Tourette syndrome are observed, then a different confidence interval would be produced from each group. About ____ percent of these confidence intervals will contain the true population mean number of tics per hour and about ____ percent will not contain the true population mean number of tics per hour.

Use the given confidence interval to find the margin of error and the sample mean. (15.3,23.7) The sample mean is . (Type an integer or a decimal.) The margin of error is. (Type an integer or a decimal.)

A random sample of 100 employees at a company shows that 62 are female.  Form a 90% confidence interval for the proportion of all employees who are female.  The interval is 0.62  what margin of error?  Round your answer to 3 decimal places.