n of 1 blue bead and 1 green bead is used to make a br:

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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I already did number one help me with number 2 and 3

Write and Solve Equations to Calculate the Length of Beads on a Bracelet (Page 1)
Check Work
Standard 7.EE.B.4.A
Introduction
1. A basic pattern of 1 blue bead and 1 green bead is used to make a bracelet that is 37 cm long. The
bracelet is made by repeating the basic pattern 10 times. The length of a blue bead is b cm. The
length of a green bead is 1.2 cm. Complete the equation to represent the length of the bracelet
37 =
10 (b +
1.2 )
2. Solve the equation in Problem 1 to find b, the
3. Solve the equation in Problem 1 to find b, the
length of each blue bead.
length of each blue bead.
37 D
(b +
37 =
(b+
37 =
3.7 = b +
= 10b
===>
Building Fluency
|3|
Transcribed Image Text:Write and Solve Equations to Calculate the Length of Beads on a Bracelet (Page 1) Check Work Standard 7.EE.B.4.A Introduction 1. A basic pattern of 1 blue bead and 1 green bead is used to make a bracelet that is 37 cm long. The bracelet is made by repeating the basic pattern 10 times. The length of a blue bead is b cm. The length of a green bead is 1.2 cm. Complete the equation to represent the length of the bracelet 37 = 10 (b + 1.2 ) 2. Solve the equation in Problem 1 to find b, the 3. Solve the equation in Problem 1 to find b, the length of each blue bead. length of each blue bead. 37 D (b + 37 = (b+ 37 = 3.7 = b + = 10b ===> Building Fluency |3|
Expert Solution
Step 1

The answers are marked in circle

The given equation is 37=10b+1.2

we need to solve for b 

Therefore 

3710=10b+1.210

cancelling the common factor 10 on right hand side

3710=10b+1.210

 

 

 

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