n a SIMPLE Rankine cycle, the steam throttled condition is 8 MPa and 480°C. The steam is then reheated to 2 MPa and 460 °C. If turbine exhaust is 60 °C, determine the following: a. Heat Added b. Turbine Work c. Heat Rejected d. Pump Work e. Net Work f. Efficiency use the given below provided..Not a reheat it is simple rankine

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question

In a SIMPLE Rankine cycle, the steam throttled condition is 8 MPa and 480°C. The steam is then reheated to 2 MPa and 460 °C. If turbine exhaust is 60 °C, determine the following:

a. Heat Added

b. Turbine Work

c. Heat Rejected

d. Pump Work

e. Net Work

f. Efficiency

use the given below provided..Not a reheat it is simple rankine

8 MPa and 480 °C (Table 3. Vapor) page 72
h: = 3348.4 kJ/kg
S1 = 6.6586 kJ/kg – K
O 2 MPa (Table 3. Vapor; note: s1 = s2) page 46
h2 = 2963.145 kJ/kg
@ 2 MPa and 460 °C (Table 3. Vapor; note: s3 = Sa) page 46
h3 = 3379.5 kJ/kg
S3 = 7.3147 kl/kq – K
Solving for ha
S3 = S4 = St + XSfg
7.3147 kl/kg – K = 0.8312 kl/kg – K+ x (7.0784 kl/kg – K)
x = 0.9159555832
ha = h; + x(hja)
hạ = 251.13 kl/kg + 0.9159555832 (2358.5 kJ/kg)
ha = 2411.411243 kJ/kg
@ 60°C (Table 1. Saturation Temperatures) page 3
Ps
= 0.019940 MPa
19.94 kPa
251.13 kJ/kg
= 2358.5 kJ/kg
= 0.8312 kJ/kg – K
7.0784 kJ/kg -K
= 0.0010172 m/kg
hs
Sig
V
Vs
Transcribed Image Text:8 MPa and 480 °C (Table 3. Vapor) page 72 h: = 3348.4 kJ/kg S1 = 6.6586 kJ/kg – K O 2 MPa (Table 3. Vapor; note: s1 = s2) page 46 h2 = 2963.145 kJ/kg @ 2 MPa and 460 °C (Table 3. Vapor; note: s3 = Sa) page 46 h3 = 3379.5 kJ/kg S3 = 7.3147 kl/kq – K Solving for ha S3 = S4 = St + XSfg 7.3147 kl/kg – K = 0.8312 kl/kg – K+ x (7.0784 kl/kg – K) x = 0.9159555832 ha = h; + x(hja) hạ = 251.13 kl/kg + 0.9159555832 (2358.5 kJ/kg) ha = 2411.411243 kJ/kg @ 60°C (Table 1. Saturation Temperatures) page 3 Ps = 0.019940 MPa 19.94 kPa 251.13 kJ/kg = 2358.5 kJ/kg = 0.8312 kJ/kg – K 7.0784 kJ/kg -K = 0.0010172 m/kg hs Sig V Vs
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Second law of thermodynamics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON