College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Help pleasearrow_forwardA beam of light traveling through air is incident up a transparent material with refractive index 1.52 at an angle of 0; -28.34 as shown in the image below. What is the angle of the transmitted ray (0+) as measured with respect to the direction normal to the surface of the material (dashed line in the image below). Incident ray Normal Oi | Or 0₁ Reflected ray Transmitted ray Note: It is understood that the unit of your answer is in degrees, however do not explicitly include units in your answer. Enter only a number. If you do enter a unit, your answer will be counted wrong.arrow_forwardIn the figure below, light is traveling in mediums with indexes of refraction, n, and n,. Is n¡ less than n2, n¡ greater than n,, or n, equal to n,? Why? If n, = 1.33, find n, ni n2arrow_forward
- Suppose a ray strikes the left face of the prism at 45.0∘ as shown, but is totally internally reflected on the opposite side. Part A) If the apex angle (at the top) is 64.0 ∘ , what can you say about the index of refraction of the prism?arrow_forwardThe light ray shown in the figure makes anangle of 18.0◦ with the normal line at theboundary of linseed oil and water. a) Find the angle θ1. Note that n = 1.48for the linseed oil.Answer in units of ◦arrow_forwardA beam of light traveling in the air strikes a flat slab of glass at an incident angle of 45 degrees. At the moment of leaving thr glass what is the angle of refraction?arrow_forward
- A beam of light both reflects and refracts at the surface between air and glass as shown in the figure below. If the refractive index of the glass is na, find the angle of incidence 0, in the air that would result in the reflected ray and the refracted ray being perpendicular to each other. (Use the following as necessary: n.:) 0, ng 0,arrow_forwardCalculate the angle of refraction at the air/core interface, r . critical angle, c and incident angle at the core/cladding interface, i . Will this light ray propagate down the fiber? You have the following data: nair = 1, ncore = 1.46, ncladding =1.43, incident =12o r = 8.2o, c = 78.4o, i = 81.8olight will propagate Formula summery Index of Refraction n= n sin 01= n, sin 0, o = sin1(2) Snell's Law Critical Angle Acceptance angle a= sin1 Numerical Aperture NA = sin a = ni- nịarrow_forwardUsing the figure below, find the angles of refraction for a light ray passing from air into glass with the following angles of incidence: 5°, 10°, and 20°. 45 40 35 30 25 20 15 10 10 20 30 40 50 60 70 80 90 Angle in air (*) O10° %3D 020° Do you notice a trend in the resulting values? If so, describe it. O Doubling the angle of incidence approximately halves the angle of refraction. O Doubling the angle of incidence approximately doubles the angle of refraction. O Doubling the angle of incidence approximately quadruples the angle of refraction. There is no trend in the resulting values. Based on your observations, what would you predict the angle of refraction to be for an angle of incidence of 40°? How does your value compare with that inferred from the figure? () ssed u asuyarrow_forward
- A goldfish is swimming inside a spherical bowl of water having an index of refraction n = 1.333. Suppose the goldfish is p = 10.7 cm from the wall of a bowl of radius |R| = 19.2 cm, as in the figure below. Neglecting the refraction of light caused by the wall of the bowl, determine the apparent distance of the goldfish from the wall according to an observer outside the bowl.cm behind the glassarrow_forwardAnswer the TWO GIVEN QUESTIONSarrow_forward
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