A 500.0 ml adrenaline (Mw =183.2 g/mol) solution in water with a concentration of 1,00 mg / mlmust be prepared. However, you only have adrenaline tartrate (Mw 333.3 g/mol) available. Howmuch adrenaline tartrate should be used to make a solution with similar volume and adrenalineconcentration?a. 0,0969 mg/Lb. 5,45 mg/L*c. 545 mg/Ld. 9,69*10“ mg/Le. 64,59 mg/L

1 mol adrenaline tartrate contains 1 mol of adrenaline. Now, Concentration of adrenaline solution =…

must be prepared. However, you only have adrenaline tartrate (Mw 333.3 g/mol) available. How %3D much adrenaline tartrate should be used to make a solution with similar volume and adrenaline concentration?

must be prepared. However, you only have adrenaline tartrate (Mw 333.3 g/mol) available. How %3D much adrenaline tartrate should be used to make a solution with similar volume and adrenaline concentration?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

A 500.0 ml adrenaline (Mw =183.2 g/mol) solution in water with a concentration of 1,00 mg / ml
must be prepared. However, you only have adrenaline tartrate (Mw 333.3 g/mol) available. How
much adrenaline tartrate should be used to make a solution with similar volume and adrenaline
concentration?
a. 0,0969 mg/L
b. 5,45 mg/L
*c. 545 mg/L
d. 9,69*10“ mg/L
e. 64,59 mg/L

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