Mr. Roby is trying to estimate the difference in theproportion of his male students who on average sleepfewer than 6 hours per night compared with his femalestudents. He selects a random sample of 20 of his 75male students and finds that 5 of them sleep fewer than 6hours per night. He selects another random sample of 17of his 100 female students and finds that 8 of them sleepfewer than 6 hours a night.Check the conditions for constructing a confidenceinterval for the difference in proportions.Random condition:10% condition: |Large Counts condition:Are all the conditions for inference met?

Random Condition In the given case both the sample, for male and female students, was obtained…

Answered: Mr. Roby is trying to estimate the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Nearly one-half of Americans ages 25 to 29 are unmarried. How large a sample is necessary to estimate the true proportion of unmarried Americans in this age group within 2 percentage points with 95% confidence?
A random sample of n1 278 people who live in a city were selected and 98 identified as a "dog person." A random sample of n2 = 109 people who live in a rural area were selected and 65 identified as a "dog person." Find the 90% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < pi – p2 < Submit Question
A university health services physician is concerned about how much sleep freshman are getting. She asked a simple random sample of 100 students if they got at least 8 hours of sleep the previous night. then she constructs a 90% confidence interval for the true proportion of all freshman college students who got at least 8 hours of sleep the previous night. Explain what would happen to the width of the interval if the sample size would decrease to 25 students
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Alfredo wants a 85% confidence interval for the true average gas mileage for a Gremlin after randomly sampling 9 Gremlins. It is known that the true sigma for Gremlin gas mileage is 4 mpg, and the average of the 9 Gremlins in Alfredo's study was 24 mpg. Find the confidence interval assuming the distribution is normal.
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Pedro was working on a report on Swiss and Austrian psychiatrists. He decided to find a 90 percent confidence interval for the difference in mean age at the time of significant psychiatric discoveries for Swiss versus Austrian psychiatrists. He found the ages at the time of psychological discovery of all the members of both groups and found the 90 percent confidence interval based on a t-distribution using a calculator. The procedure he used is not appropriate in this context because O The sample sizes for the two groups are not equal. O The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used. O Age at the time of psychological discovery occurs at different intervals in the two countries, so the distribution of ages cannot be the same. O Age at the time of psychological discovery is likely to be skewed rather than bell shaped, so the assumptions for using this confidence interval formula are not…
One scientist wondered if there was a difference in the average daily intake of dairy products between men and women. He took a sample of n1 = 50 adult men and n2 = 50 adult women and recorded their daily intake of dairy products in grams per day. A summary of the sample results is presented in the table. Construct a 95% confidence interval for the difference in the average daily intake of dairy products for men and women. Can it be concluded that there is a difference in the average daily intakes for men and women?
If the number of smokers in a sample of 40 students selected from university A is 14 and the number of smokers in a sample of 380 students selected from university B is 84. Then the 99% confidence interval for the difference between proportions of smokers in the two universities (PB-PA) is closest to O a. (-0.3110,0.0534) O b. (-0.3310,0.0729) O c. (-0.1430,-0.1150) O d. (-0.1450,-0.1130) Oe. None of these
A certain counselor wants to compare mean IQ scores for two different social groups. A random sample of 15 IQ scores from group 1 showed a mean of 117 and a standard deviation of 17 , while an independently chosen random sample of 9 IQ scores from group 2 showed a mean of 112 and a standard deviation of 15 . Assuming that the populations of IQ scores are normally distributed for each of the groups and that the variances of these populations are equal, construct a 90% confidence intervalfor the difference −μ1μ2 between the mean μ1 of IQ scores of group 1 and the mean μ2 of IQ scores of group 2 . Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your responses to at least two decimal places. (If necessary, consult a list of formulas.)
A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?
Mr. Roby is trying to estimate the difference in the proportion of his male students who on average sleep fewer than 6 hours per night compared with his female students. He selects a random sample of 20 of his 75 male students and finds that 5 of them sleep fewer than 6 hours per night. He selects another random sample of 17 of his 100 female students and finds that 8 of them sleep fewer than 6 hours a night. Check the conditions for constructing a confidence interval for the difference in proportions. Random condition: A) metB) not metC) does not apply 10% condition: A) metB) not metC) does not apply Large Counts condition: A) metB) not metC) does not apply Are all the conditions for inference met? A) YesB) NoC) Not enough information

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