More than one teacher has given the following advice: choose answer C when blindly guessing among four answers in a multiple choice test, since C is more often the correct answer than either A, B, or D. Suppose that we take a random sample of 580 correct answers from multiple-choice tests for introductory college courses and obtain the information summarized by the first row of numbers in the table below. These numbers are the observed frequencies for the categories A, B, C, and D for our sample of 580 correct answers. The second row of numbers contains the frequencies expected for a sample of 580 correct answers if a correct answer is equally likely to be A, B, C, or D. The bottom row of numbers contains the following value for each of the correct answer categories A, B, C, and D.
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- Suppose we want to compare the GPA for students in at least three different social classes (Upper, Middle, Working). We obtain GPA records for a randomly selected set of 30 students, ten from each social class group. What test should you use and why?arrow_forwardA sample of 296 students at a university is surveyed. The students are classified according to gender ("female" or "male"). They are also classified according to major ("biology", "business", "engineering", "mathematics", or "computer science"). The results are given in the contingency table below. Biology Business Engineering Mathematics Female 33 30 22 45 Male 24 43 26 16 Among all the students in the sample, what is the relative frequency of male computer science majors? Round your answer to two decimal places. 1 X Computer science 41 16 Españ Aaarrow_forwardVirginia polled a large sample of individuals to find the percentage of students with known food allergies and the percentage of students without known food allergies. Which of the following could sufficiently display the data if only the two given categories are to be included? Select the correct answer below: bar graph pie chart either a pie chart or a bar graph neither a pie chart nor a bar grapharrow_forward
- A biologist is studying the composition of birds on a lake and counts 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons. From previous studies performed around the same time of the year, she expects 50% of the birds to be ducks, 23% to be geese, 12% to be cranes, 10% to be swans, and 5% to be herons. What are the expected and observed counts? Select one. Expected = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons Observed = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Expected = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Observed 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons %3D Expected = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons Observed = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons %3D %3D Expected = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Observed = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 heronsarrow_forwardMore than one teacher has given the following advice: choose answer C when blindly guessing among four answers in a multiple choice test, since C is more often the correct answer than either A, B, or D. Suppose that we take a random sample of 600 multiple-choice test answers (the correct answers from the instructor's answer sheet) from introductory college courses and obtain the information summarized by the first row of numbers in the table below. These numbers are the observed frequencies for the categories A, B, C, and D for our sample of 600 correct answers. The second row of numbers contains the frequencies expected for a sample of 600 correct answers if a correct answer is equally likely to be A, B, C, or D. The bottom row of numbers contains the following value for each of the correct answer categories A, B, C, and D. −fOfE2 fE = −Observed frequencyExpected frequency2 Expected frequencyarrow_forwardSample surveys on sensitive issues can give different results depending on how the question is asked. A University of Wisconsin study randomly divided 2400 respondents into three groups. All participants were asked if they had ever used cocaine. One group of 800 was interviewed by phone; 21% said they had used cocaine. Another 800 people were asked the question in a one-on-one personal interview; 25% said “Yes.” The remaining 800 were allowed to make an anonymous written response; 28% said “Yes.”101. Was this an experiment or an observational study? Justify your answer.2. Make a two-way table of responses about cocaine use by how the survey was administered.3. Are the differences between the three groups statistically significant? Give appropriate evidence to support your answerarrow_forward
- One cable company advertises that it has excellent customer service. In fact, the company advertises that a technician will be there within 30 minutes of when a service call is placed. One frustrated customer believes this is not the truth, claiming that it takes over 30 minutes for the cable repairman to arrive. The customer asks 15 of his neighbors how long it has taken for the cable repairman to arrive when they have called for him. The sample mean for this group is 32.2 minutes with a sample standard deviation of 3.6 minutes. Test the customer’s claim at the 0.02 level of significance. (a) State the null and alternative hypotheses (b) Find the value of your test statistic. Draw a picture and label its location on the normal curve. Also shade the area where you will find the p-value. (c) Calculate the p-value from the sample data. Compare it to the significance level. Label it’s value and location on your bell curve (d) Write a full…arrow_forwardLast school year, the student body of a local university consisted of 35% freshmen, 24% sophomores, 26% juniors, and 15% seniors. A sample of 300 students taken from this year's student body showed the following number of students in each classification. Freshmen 90 Sophomores 60 Juniors 90 Seniors 60 We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. The calculated value for the test statistic equals a. 0.5444 b. 2.789 c. 10.989 d. 15.231arrow_forwardHello, I was told to repost again for the multiple choice question for the Two Way Frequency table. Thank you in advance!arrow_forward
- When I was an undergraduate, I helped my father conduct some Child Psychology research about parental influence on gender bias. In this study we interviewed 158 kindergarteners. Our initial question was "What is your favorite color?" where we studied the distribution of "Pink" and "Blue" responses. To our surprise, 38 of the students interviewed responded "Turquoise". Use this information to select the response which correctly answers the question. Being curious, we decided to further interview the children who responded "Turquoise". While he took a lunch break, he told me to select 5 such children to form a group for interviews. How many different possible groups could I have formed? O 769754986 O 5.297 x 1036 O 501942 O 1109750arrow_forwardA real-estate appraiser wants to verify the market value for homes on the east side of the city that are very similar to size and style. The appraiser wants to test the popular belief that the average sales price is $37.80 per square foot for such homes. Suppose that a random sample of six sales were selected. The sampled sales prices per square foot are $35.00, $38.10, $37.20, $29.80, $30.30, and $35.40. Assuming a normal distribution is a good model for sales, test the claim that the mean sales price per square foot differs from $37.80 at the 1% significance level.arrow_forwardYou may need to use the appropriate technology to answer this question. During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00 p.m. audience proportions were recorded as ABC 31%, CBS 26%, NBC 27%, and independents 16%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 97 homes, CBS 68 homes, NBC 91 homes, and independents 44 homes. Test with a = 0.05 to determine whether the viewing audience proportions changed. State the null and alternative hypotheses. 0.31, PCBS = 0.26, PNBC = 0.27, PIND 0.27, PIND = 0.16. Ho: : The proportions are not pPABC Наi РАВС 3 0.31, РсвS 0.26, PNBC 0.16 0.27, 0.16 Но: РАВС 0.31, Рсвs 3D 0.26, Наi РАВС + 0.31, РсвS PNBC + 0.26, PNBC ± 0.27, , PIND + 0.16 Ho: PABC + 0.31, PCBS + 0.26, PNBC + 0.27, PIND + 0.16 0.26, PNBC 0.27, PIND = 0.16 %D На РАВС - 0.31, РсBs 0.26, PNBC 0.27, PIND 0.16 Нo: РАВС - 0.31, РсBS H: The proportions are not PABC 0.16. 0.31,…arrow_forward
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