2.00 M = x / 10.0 Lx = 20.0 molSuppose the molarity was listed as 2.0 M (two sig figs). How todisplay the answer? Like this:20. MolProblem #5: How many moles of Na,CO, are in 10.0 mL of a2.0 M solution? Problem #1: Sea water contains roughly 28.0 g of NaCl per liter. What isthe molarity of sodium chloride in sea water?Solution:Problem #2: What is the molarity of 245.0 g of H,So, dissolvedin 1.000 L of solution?Problem #3: What is the molarity of 5.00 g of NaOH in 750.0mL of solution?Problem #4 How many moles of Na,CO, are there in 10.0 L of 2.00Msolution?Solution:M = moles of solute / liters of solution

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

2.00 M = x / 10.0 L
x = 20.0 mol
Suppose the molarity was listed as 2.0 M (two sig figs). How to
display the answer? Like this:
20. Mol
Problem #5: How many moles of Na,CO, are in 10.0 mL of a
2.0 M solution?

Problem #1: Sea water contains roughly 28.0 g of NaCl per liter. What is
the molarity of sodium chloride in sea water?
Solution:
Problem #2: What is the molarity of 245.0 g of H,So, dissolved
in 1.000 L of solution?
Problem #3: What is the molarity of 5.00 g of NaOH in 750.0
mL of solution?
Problem #4 How many moles of Na,CO, are there in 10.0 L of 2.00M
solution?
Solution:
M = moles of solute / liters of solution

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