Minimize z = 24X1 + 28X2 subject to 5X1 + 4X2 <= 2,000 X1 + X2 >= 300 X1 >= 100 X1, X2 >=0 Solve the above problem with the simplex method. Provide the value of the basic variables(BV) at tableau #3 and the optimal solution of the LP. Notes: Set M = 100. Tableau #1 is the initial tableau where an inconsistency exists on row z. Tableau #2 is the tableau where the inconsistency on row z is fixed. Set s1 as the slack variable for constraint 1

Minimize z = 24X1 + 28X2 subject to 5X1 + 4X2 <= 2,000 X1 + X2 >= 300 X1 >= 100 X1, X2 >=0 Solve the above problem with the simplex method. Provide the value of the basic variables(BV) at tableau #3 and the optimal solution of the LP. Notes: Set M = 100. Tableau #1 is the initial tableau where an inconsistency exists on row z. Tableau #2 is the tableau where the inconsistency on row z is fixed. Set s1 as the slack variable for constraint 1

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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When deleting a basic variable xBr from the simplex tableau, would it be possible to make xBr nonbasic by pivoting on any non-zero element in row r? What difficulties one might encounter with this approach?
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SIMPLEX METHOD Min C = 3X1 + 7X2 + 5X3 Subject to: X1 + X2 + X3 ≥ 50 2X1 + 3X2 + X3 > 100 X1, X2, X3 ≥ 0 8. What is the pivot element/number? a. 2/3 b. 1/3 c. 1
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