Minimize g - 20x + 30y +36z subject to: x+2y +3z  ≥ 48 2x + 2y +3z  ≥ 70 2x +3y +4z  ≥ 96

Maximize f = 5x1 - 20x2 subject to -2x1 + 10x2 <= 5, 2x1 + 5x2 <= 10

Find three numbers which add to 100 and whose product is maximized.

2) REVIEW: On quiz 6 the profit function was y= x*(660-3x)-(8000+110x). We can multiply this out as y= 660x-3x-8000-110x. Use the POWER RULE to find x (the number of TVS to sell to get the most profit.) On quiz 6 we used the calculator's maximum program; we should get the same answer here using calculus.