until the iron reaches TFe = 150°C. When the iron cubereaches TFe = 150°C, quickly release the heat slider and click ondetermine the specific heat of the brick, Cbr.Click on "Energy Symbols" and “Link Heaters". Heat both cubesQbr = mbrCbrAT = mbrCbr( Tbr - T;) = QFeCalculate the specific heat Cbr for the brick, using the samemethod used for the iron cube. Because the heaters were linked,the total energy absorbed by each cube is the same:Use the values of mbr, QFe and Tbr from the previous calculations toLab 11 Instrent ee.9-mc 4Tmc ATAnswer:lenstem1001 emse enM-mas sQ-heat transtr=130the Pause button.If vou overshoot, you can cool the cubes down by moving theslider down or you can just let the heat dissipate and Pause theexperiment when you get to the desired temperature.If you need to repeat the measurement, click the orange Resetbutton and start fresh with both cubes at room temperature (i.e.,the first tick mark) janaoyC.When the iron cube reaches TFe = 150°C, what is thetemperature of the brick cube?Answer:d.%3D%3DQFe =mbrCbr(Tbr- Ti)Cor = QFe/[mbr(Tbr -Answer: Lab 11 Instructions: Specific HeatDue: See Course Schedulennw c.bedThe bottom-most (first) ticku markeronsthe thermometer00 2 no corresponds to the initial room temperature, Ti and the forth tickno corresponds to T = 100°C? What is the value of each tick mark?Answer:20°CNow, that the thermometer is calibrated we can read thetemperature of the other materials. We'll assume everything in -mthe room starts out at the same room temperature, T: (in Celsius2ede tod degrees). saH niJ" bns "eloedu nori ərlt nerdW O 2 T aerlaser noti erli liinuDetermine the Specific Heat eloybloiup, 0a Teerlo591nottud eeue9 gd1.3 To find the specific heat of the brick and the oil, we need to figure outerl eexactly how much heat energy we are adding when the heat slider onthe bucket is moved.nenw inemheqxeJeasThe heat slider isn't calibrated, but we can link the heaters, whichmeans they will generate identical heat output for both buckets. So ifwe place the iron on one stand, and the brick on the other one, theywill receive the same amount of energy when we turn up the heat. Nowwe only need to figure out how much energy one of the cube absorbs.e.i)eniVolume brioK 103phd eri 1ol E Siseceemsa en pniau.benil anew 1oleer seueo08 o noni orit hal beau borttemtemea ei eduo dose E bedioads vpmene istol arlBrickIronn to eeole eaUof andWaterOlive OilHeatHeatCoolCoolPage 5 of 9nts

Question

until the iron reaches TFe = 150°C. When the iron cubereaches TFe = 150°C, quickly release the heat slider and click ondetermine the specific heat of the brick, Cbr.Click on &#34;Energy Symbols&#34; and “Link Heaters&#34;. Heat both cubesQbr = mbrCbrAT = mbrCbr( Tbr - T;) = QFeCalculate the specific heat Cbr for the brick, using the samemethod used for the iron cube. Because the heaters were linked,the total energy absorbed by each cube is the same:Use the values of mbr, QFe and Tbr from the previous calculations toLab 11 Instrent ee.9-mc 4Tmc ATAnswer:lenstem1001 emse enM-mas sQ-heat transtr=130the Pause button.If vou overshoot, you can cool the cubes down by moving theslider down or you can just let the heat dissipate and Pause theexperiment when you get to the desired temperature.If you need to repeat the measurement, click the orange Resetbutton and start fresh with both cubes at room temperature (i.e.,the first tick mark) janaoyC.When the iron cube reaches TFe = 150°C, what is thetemperature of the brick cube?Answer:d.%3D%3DQFe =mbrCbr(Tbr- Ti)Cor = QFe/[mbr(Tbr -Answer: Lab 11 Instructions: Specific HeatDue: See Course Schedulennw c.bedThe bottom-most (first) ticku markeronsthe thermometer00 2 no corresponds to the initial room temperature, Ti and the forth tickno corresponds to T = 100°C? What is the value of each tick mark?Answer:20°CNow, that the thermometer is calibrated we can read thetemperature of the other materials. We'll assume everything in -mthe room starts out at the same room temperature, T: (in Celsius2ede tod degrees). saH niJ&#34; bns &#34;eloedu nori ərlt nerdW O 2 T aerlaser noti erli liinuDetermine the Specific Heat eloybloiup, 0a Teerlo591nottud eeue9 gd1.3 To find the specific heat of the brick and the oil, we need to figure outerl eexactly how much heat energy we are adding when the heat slider onthe bucket is moved.nenw inemheqxeJeasThe heat slider isn't calibrated, but we can link the heaters, whichmeans they will generate identical heat output for both buckets. So ifwe place the iron on one stand, and the brick on the other one, theywill receive the same amount of energy when we turn up the heat. Nowwe only need to figure out how much energy one of the cube absorbs.e.i)eniVolume brioK 103phd eri 1ol E Siseceemsa en pniau.benil anew 1oleer seueo08 o noni orit hal beau borttemtemea ei eduo dose E bedioads vpmene istol arlBrickIronn to eeole eaUof andWaterOlive OilHeatHeatCoolCoolPage 5 of 9nts

Accepted Answer

Solution:
The amount of heat energy absorbed by the iron cube can be calculated using the following…