Methanol is used to heat food. The combustion of methanol can be described by the following thermochemical equation:2CH3OH() + 3O2(g) → 2CO2(g) + 4H2O(g) AH° = -1199 kJHow much methanol, in grams, is needed to release 573 kJ of heat?ig of CH3OHmass =eTextbook and MediaSave for LaterAttempts: 0 of 15 usedSubmit Answerост26

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Methanol is used to heat food. The combustion of methanol can be described by the following thermochemical equation: 2CH3OH(I) + 3O2(8) 2CO2(3) + 4H20(g) AH° = -1199 kJ How much methanol, in grams, is needed to release 573 kJ of heat?

Methanol is used to heat food. The combustion of methanol can be described by the following thermochemical equation: 2CH3OH(I) + 3O2(8) 2CO2(3) + 4H20(g) AH° = -1199 kJ How much methanol, in grams, is needed to release 573 kJ of heat?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Methanol is used to heat food. The combustion of methanol can be described by the following thermochemical equation:
2CH3OH() + 3O2(g) → 2CO2(g) + 4H2O(g) AH° = -1199 kJ
How much methanol, in grams, is needed to release 573 kJ of heat?
i
g of CH3OH
mass =
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