Memory Address Value CPU Registers 300 1940 300 PC 301 5941 AC 302 2941 1940 IR 940 0003 941 0002
I need help showing the following problem in a diagram(all 6 steps) the first step was already done.
1.The PC contains 300, the address of the first instruction. This instruction
(the value 1940 in hexadecimal) is loaded into the IR (Instruction set register), and the PC is
incremented. Note that this process involves the use of a memory address register and a
memory buffer register. For simplicity, these intermediate registers are ignored.
2. The first 4 bits (first hexadecimal digit) in the IR indicate that the AC is to be loaded.
00012 = 110 =Load AC from memory
00102 = 210= Store AC to memory
01012 = 510 = Add to AC from memory
The remaining 12 bits (three hexadecimal digits) specify the address (940) from which data are
to be loaded.
3. The next instruction (5941) is fetched from location 301, and the PC is incremented.
4. The old contents of the AC and the contents of location 941 are added, and the result is
stored in the AC.
5. The next instruction (2941) is fetched from location 302, and the PC is incremented.
6. The contents of the AC are stored in location 941
Step by step
Solved in 2 steps
