Members of the We-Luv-Plants club are interested in comparing the tendency of males vs. females to choose a vegetarian diet. They randomly sampled 75 males and 75 females at their school. The data showed that 23 of the girls were vegetarians whereas only 12 of the boys could stay away from a tasty burger.  Construct and interpret a 95% confidence interval for the difference in the proportions between girls and boys who are vegetarians (you might want to include ALL steps here). Does this confidence interval provide evidence that girls are more likely than boys to choose a vegetarian diet? Explain. To what population(s) do your conclusions in parts a and b apply?

Q: Isabel Myers was a pioneer in the study of personality types. According to one of her surveys, in a…

A: Solution

Q: 2. Suppose that you take a random sample of 360 people who voted in the last election in a heavily…

A:

Q: Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given claim: 50% of the parents who had children in grades K-12 were satisfied with the quality of…

Q: There are 3000 beads of various colors in a jar. In a sample of 125 beads, 40% were red. Calculate…

A:

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Given Data: x=722 n=1762   p^=7221762=0.4098

Q: A local news outlet reported that 56% of 600 randomly sampled Kansas residents planned to set off…

A: We have given that,  Sample proportion (p̂) = 56% = 0.56 and sample size (n) = 600 Then,  We will…

Q: In a random sample of 100 customers, the items that customers purchased were tracked. It was found…

A: Given,sample size(n)=100sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: Several years ago, 36% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: In a survey of 1,200 social media users, 56% said it is not okay to be friends with your boss.…

A:

Q: You are the manager of a grocery store. Lately, customers have been complaining about the eggs they…

A:

Q: A sample of 80 respondents was taken to determine whether the clients of an internet provider are…

A: Given that  Sample size (n) = 80 Respondents satisfied with the service (x) = 60 Sample proportion…

Q: As Senior Class President, one of your lifelong duties is overseeing the planning of your high…

A:

Q: Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of…

A: From the provided information, 39% of parents who had children in grades K-12 were satisfied with…

Q: A survey of 400 students at Red Rock College found that 180 planned to take summer classes. Find a…

A:

Q: A student polls his school to see if students in the school district are for or against the new…

A: Given: n=600 and x=480. Then,p^=xn=480600=0.8

Q: Cameron and Bailey each take random samples and construct 90% confidence intervals for the…

A:

Q: a recent study of 100 people in Burlingame found that 19 were obese.  Find the 90% confidence…

A:

Q: Suppose I wanted to know the proportion of students who are paying attention in class, so I give a…

A: Confidence Interval for Proportion A confidence interval is a statistical method that denotes a…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: Out of all the students that attend Yale University, 1,982 were selected to participate in a school…

A:

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: At a large university in Conway, South Carolina, the Dean wants to know what proportion of students…

A: We have given thatn = 200x = 145Confidence level (c) = 99% = 0.99Significance level (α) = 1 - c =  1…

Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…

A: We want to calculate the 90% confidence interval for each of the following proportions

Q: sample of 624 applicants to the Durmstrang Institute of Sorcery, 133 were accepted. Construct a 90%…

A: Given that  X=133 , n=624 , p=20%=0.20

Q: A consumer group selected 100 different airplanes at random from each of two large airlines. The…

A: We know that the formula of confidence interval for difference in population mean- Since here n is…

Q: n a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A:

Q: A medical researcher claims that smoking can result in the wrinkled skin around the eyes. The…

A: Given Information: Smokers: n1=150 x1=95 Nonsmokers: n2=250 x2=105 Confidence level is 95%

Q: a newspaper article stated that the us supreme court received 812 letters from around the country on…

A: To find the 95% confidence interval for the true proportion of all American adults who feel that…

Q: What formulas are used to find the confidence interval? Researchers comparing the effectiveness of…

A: According to the given information in this questionWe need to construct 95% confidence interval

Q: The branch manager of an outlet store​ (Store 1) of a nationwide chain of pet supply stores wants to…

A: Comment: As per the our company guidelines we are supposed to answer only three subparts. Kindly…

Q: Commerce students were asked if they watch or listen to the state of the nation address (SONA), of…

A: Given: n= 220 ,x= 105 At 90.0 % confidence level , z score= 1.645 Need to find confidence interval…

Q: Several years ago, 44% of parents who had children in grades K-12 were satisfied with the quality of…

A: We have given that 44% of parents who had children in grades K-12 were satisfied with the quality of…

Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…

A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…

Q: 7 out of 70 students said they were comfortable with “working in a workplace with a lot of…

A: Given that  57 out of 70 students said they were comfortable with “working in a workplace with a lot…

Q: Leana is interested in the proportion of people who live in her area who own a dog. She randomly…

A: Suppose p is the population proportion of people who live within one mile of Person L’s home who own…

Q: A high school counselor is interested in determining factors that contribute to high school drop out…

A: Solution; Given information: n1=41 Sample size of high school  graduatesn2= 38 Sample size of high…

Q: A major grocery store chain is trying to cut down on waste. Currently, they get peaches from two…

A: Option (d) We are 95% confident that the proportion of on-sell able items for Whole Fruits is…

Q: A marketing survey involves product recognition in New York and California. Of 679 New Yorkers…

A: given data  n1 = 679    x1 = 256p^1 = x1n1 = 256679 = 0.3370 n2 = 631    x2 = 208 p^2 = x2n2 =…

Q: Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

Q: In the past, 70% of a garage's business was with former patrons. Clarence Wade, the owner of the…

A: Solution: Given information: n= 600 Sample size  x = 432 Successes  p^=xn=432600= 0.72 Sample…

Q: According to a recent Government survey, 6% of all merchandise sold in the U.S. gets returned.  A…

A: It is given that sample size (n) is 80 and x is 12.

Q: In a study of the relationship between alcohol use and bicycling fatalities, the researcher…

A: