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PLEASE ANSWER IT ASAP FOR AN UPVOTE.
Transcribed Image Text:R-134a enters a compressor
operating at steady state at -4°C. At
this state, 7% of the mass is in the
liquid phase. R-134a then exits at a
pressure of 1600 kPa. If the actual
exit temperature is 70°C, determine
the (a) isentropic compressor
efficiency in %, (b) the work input, in
kJ/kg of refrigerant flowing and the
(c) change in the entropy of the
refrigerant, in kJ/kg-K. Heat transfer
between the compressor and its
surroundings as well as the kinetic
and potential energy effects can be
ignored.
Answers:
Energy Balance Equation:
Entropy Balance Equation:
DO NOT insert extra space in
between variable, e.g. Q-W+minhin-
mouthout=mfhf-mihi. Use i and f to
denote the initial and final states, in
and out for the entry and exit points.
State at the Inlet:
State at the Outlet (isentropic):
State at the Outlet (actual):
Isentropic efficiency =
Win
kJ/kg
%3D
As =
kJ/kg-K
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