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me on interpreting my solved solutions for a, b, c, and d areas. I am still confused as to how I can properly interpret. There isn't a need to solve, just a simple help in me understanding my results. (Please read carefully, there's f

me on interpreting my solved solutions for a, b, c, and d areas. I am still confused as to how I can properly interpret. There isn't a need to solve, just a simple help in me understanding my results. (Please read carefully, there's f

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter7: Percents
Section: Chapter Questions
Problem 10PTTS
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Can someone please help me on interpreting my solved solutions for a, b, c, and d areas. I am still confused as to how I can properly interpret. There isn't a need to solve, just a simple help in me understanding my results. (Please read carefully, there's four differing sections)

Observations from The null hypothesis is Ho: H1 = H, and the alternative hypothesis is as specified. The provided data are from a simple random paired sample from the two populations under consideration. Use the paired t-test to perform the required hypothesis test at the 10% significance level. Pair Population 1 Population 2 1 24 2 9 10 3 20 19 E Click the icon to view the t-table. 4 13 8 5 8 14 14 10 15 8 22 28 Find the test statistic. Use population 1- population 2 as the difference. t= 0.088 c.) (Round to three decimal places as needed.) Find the critical value(s). The critical value(s) is/are 1.415 (Round to three decimal places as needed. Use a comma to separate answers as needed.) What is the correct conclusion for the hypothesis test? O A. Do not reject Hn. There is not sufficient evidence that H > 3. XO B.-Rejeett- idence that P2 O c. Reject Ho- There is sufficient evidence that p1 > H2. O D. Do not reject Ho. There is sufficient evidence that µ, > H2. Observations from The null hypothesis is H,: H1 = H2 and the alternative hypothesis is as specified. The provided data are from a simple random paired sample from the two populations under consideration. Use the paired t-test to perform the required hypothesis test at the 10% significance level. Pair Population 1 Population 2 6. Hai H1 # H2 2 7 6 12 9 E Click the icon to view the t-table. 4 14 8 22 18 11 12 1 Find the test statistic. Use population 1- population 2 as the difference. t= 3.058 d.) (Round to three decimal places as needed.) Find the critical value(s). The critical value(s) is/are 1.943, - 1.943 (Round to three decimal places as needed. Use a comma to separate answers as needed.) What is the correct conclusion for the hypothesis test? O A. Reject Ho- There that H, H2- reject Ho- There is not sufficient evidence that H # H2: not sufficient Do OC. Reject Ho. There is sufficient evidence that µ, # H2. O D. Do not reject Hn. There is sufficient evidence that H + H2.
Transcribed Image Text:Observations from The null hypothesis is Ho: H1 = H, and the alternative hypothesis is as specified. The provided data are from a simple random paired sample from the two populations under consideration. Use the paired t-test to perform the required hypothesis test at the 10% significance level. Pair Population 1 Population 2 1 24 2 9 10 3 20 19 E Click the icon to view the t-table. 4 13 8 5 8 14 14 10 15 8 22 28 Find the test statistic. Use population 1- population 2 as the difference. t= 0.088 c.) (Round to three decimal places as needed.) Find the critical value(s). The critical value(s) is/are 1.415 (Round to three decimal places as needed. Use a comma to separate answers as needed.) What is the correct conclusion for the hypothesis test? O A. Do not reject Hn. There is not sufficient evidence that H > 3. XO B.-Rejeett- idence that P2 O c. Reject Ho- There is sufficient evidence that p1 > H2. O D. Do not reject Ho. There is sufficient evidence that µ, > H2. Observations from The null hypothesis is H,: H1 = H2 and the alternative hypothesis is as specified. The provided data are from a simple random paired sample from the two populations under consideration. Use the paired t-test to perform the required hypothesis test at the 10% significance level. Pair Population 1 Population 2 6. Hai H1 # H2 2 7 6 12 9 E Click the icon to view the t-table. 4 14 8 22 18 11 12 1 Find the test statistic. Use population 1- population 2 as the difference. t= 3.058 d.) (Round to three decimal places as needed.) Find the critical value(s). The critical value(s) is/are 1.943, - 1.943 (Round to three decimal places as needed. Use a comma to separate answers as needed.) What is the correct conclusion for the hypothesis test? O A. Reject Ho- There that H, H2- reject Ho- There is not sufficient evidence that H # H2: not sufficient Do OC. Reject Ho. There is sufficient evidence that µ, # H2. O D. Do not reject Hn. There is sufficient evidence that H + H2.
A scientist investigated the effect of cross-fertilization on the heights of plants. In one study, the scientist planted 15 pairs of a species of plant. Each pair consisted of one cross-fertilized plant and one self-fertilized plant grown in the same pot. The table available below gives the height differences, in eighths of an inch, for the 15 pairs. Each difference is obtained by subtracting the height of the self-fertilized plant from that of the cross-fertilized plant. Use the paired t-interval procedure to determine a 99% confidence interval for the difference between the mean heights of cross-fertilized and self-fertilized plants. Interpret the result. (Note: d = 20.13 and sa = 35.80.) Click here to view the data, Click here to view a table of critical values oft. The 99% confidence interval is from - 7.39 eighths of an inch to 47.65 eighths of an inch. (Round to two decimal places as needed. Use ascending order.) Which statement below best interprets the confidence interval? a.) O A. There is 99% confidence that the difference between the heights of cross-fertilized and self-fertilized plants is in the interval. O B. There is 99% confidence that the difference between the heights of a cross-fertilized plant and a self-fertilized plant is in the interval. O C. There is 99% confidence that the difference between the mean heights of cross-fertilized plants and self-fertilized plants is in the interval. O D. There is 99% confidence that a pair of cross-fertilized and self-fertilized plants has a difference in heights that is in the interval. Obtain the required confidence interval. Interpret your result. The accompanying data provide the weights, in pounds, of 17 anorexic women before and after receiving a therapy treatment for anorexia nervosa. Find a 90% confidence interval for the weight gain that would be obtained, on average, by using the family therapy treatment. E Click the icon to view the data. Find the 90% confidence interval. Use Before - After. - 10.29, - 4.23 ) pounds b.) (Round to two decimal places as needed.) Interpret your result. Choose the correct answer below. O A. We can be 10% confident that the weight gain that would be obtained, on average, by using the family therapy treatment is somewhere between the endpoints of the confidence interval. O B. There is a 90% probability that the weight gain that would be obtained by using the family therapy treatment is somewhere between the endpoints of the confidence interval. O C. Ninety percent of the women gained weight somewhere between the endpoints of the confidence interval. O D. We can be 90% confident that the weight gain that would be obtained, on average, by using the family therapy treatment is somewhere between the endpoints of the confidence interval.
Transcribed Image Text:A scientist investigated the effect of cross-fertilization on the heights of plants. In one study, the scientist planted 15 pairs of a species of plant. Each pair consisted of one cross-fertilized plant and one self-fertilized plant grown in the same pot. The table available below gives the height differences, in eighths of an inch, for the 15 pairs. Each difference is obtained by subtracting the height of the self-fertilized plant from that of the cross-fertilized plant. Use the paired t-interval procedure to determine a 99% confidence interval for the difference between the mean heights of cross-fertilized and self-fertilized plants. Interpret the result. (Note: d = 20.13 and sa = 35.80.) Click here to view the data, Click here to view a table of critical values oft. The 99% confidence interval is from - 7.39 eighths of an inch to 47.65 eighths of an inch. (Round to two decimal places as needed. Use ascending order.) Which statement below best interprets the confidence interval? a.) O A. There is 99% confidence that the difference between the heights of cross-fertilized and self-fertilized plants is in the interval. O B. There is 99% confidence that the difference between the heights of a cross-fertilized plant and a self-fertilized plant is in the interval. O C. There is 99% confidence that the difference between the mean heights of cross-fertilized plants and self-fertilized plants is in the interval. O D. There is 99% confidence that a pair of cross-fertilized and self-fertilized plants has a difference in heights that is in the interval. Obtain the required confidence interval. Interpret your result. The accompanying data provide the weights, in pounds, of 17 anorexic women before and after receiving a therapy treatment for anorexia nervosa. Find a 90% confidence interval for the weight gain that would be obtained, on average, by using the family therapy treatment. E Click the icon to view the data. Find the 90% confidence interval. Use Before - After. - 10.29, - 4.23 ) pounds b.) (Round to two decimal places as needed.) Interpret your result. Choose the correct answer below. O A. We can be 10% confident that the weight gain that would be obtained, on average, by using the family therapy treatment is somewhere between the endpoints of the confidence interval. O B. There is a 90% probability that the weight gain that would be obtained by using the family therapy treatment is somewhere between the endpoints of the confidence interval. O C. Ninety percent of the women gained weight somewhere between the endpoints of the confidence interval. O D. We can be 90% confident that the weight gain that would be obtained, on average, by using the family therapy treatment is somewhere between the endpoints of the confidence interval.
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