May I ask if the answer for this problem is q =11.44? It think the answer key is wrong of otherwise, kindly explain it to me please. Based on my undrstanding the distance should be (10-7.56) +0.120 but the book says its 2.04, how did it got the 2.04? Thank you A, 12(1) 12Ay 12(1) 12FirstA A, A+AyA12 12+6A 30Surfacthe generag peOWhenSolution:n 13.5AreaAy A+Ag2 +Asys30y 12(0.5)+y-5.7 in.4.470.6412(7) + 6(13.5)2.56Q=A;Y1 +A2Y2Q=6(1)(7.8) + 7.3(1)(3.65)Q=73.4 in10.12y=7.56250 Problem:A.Two 10 in.-15.3 channels are welded togetheras shown. Find the moment of area of theupper channel about the horizontal centroidalaxis x of the entire section.A1=D4.47A2 = 4.47A 8.94Y2 =10.120%3D2.68Ay DA,Y1 + A2Y28.94ỹ = 4.47(5) + 4.47(10.12)y = 7.56Q= AyQ=4.47(2.04)Q = 9.12 in2

You are correct as per the diagram and calculations shown

Answered: May I ask if the answer for this…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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May I ask if the answer for this problem is q =11.44? It think the answer key is wrong of otherwise, kindly explain it to me please. Based on my undrstanding the distance should be (10-7.56) +0.120 but the book says its 2.04, how did it got the 2.04? Thank you

A, 12(1) 12
Ay 12(1) 12
First
A A, A+Ay
A12 12+6
A 30
Surfac
the genera
g pe
OWhen
Solution:
n 13.5
Area
Ay A+Ag2 +Asys
30y 12(0.5)+
y-5.7 in.
4.47
0.64
12(7) + 6(13.5)
2.56
Q=A;Y1 +A2Y2
Q=6(1)(7.8) + 7.3(1)(3.65)
Q=73.4 in
10.12
y=7.56
250 Problem:
A.
Two 10 in.-15.3 channels are welded together
as shown. Find the moment of area of the
upper channel about the horizontal centroidal
axis x of the entire section.
A1=D4.47
A2 = 4.47
A 8.94
Y2 =10.120
%3D
2.68
Ay DA,Y1 + A2Y2
8.94ỹ = 4.47(5) + 4.47(10.12)
y = 7.56
Q= Ay
Q=4.47(2.04)
Q = 9.12 in2

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