may developed this program supplied materials and teacher training for a large-scale test involving nearly 9,600 employees in several different sites. Statistical analysis of the results showed that the percentage of employees who did not pass the course was reduced from 15.2% to 14.6%. The hypothesis that the program produced no improvement was rejected with a P-value of 0.028. Complete parts a) and b) below. a) Explain what the P-value means in this context. Choose the correct answer below. O A. There is only a 2.8% chance of seeing a sample proportion of 15.2% (or more) of employees failing the course by natural sampling variation if 14.6% is the true population value. OB. There is only a 2.8% chance of seeing a sample proportion of 14.6% (or less) of employees failing the course by natural sampling variation if 15.2% is the true population value. OC. There is only a 97.2% chance of seeing a sample proportion of 14.6% (or less) of employees failing the course by natural sampling variation if 15.2% is the true population value. O D. There is a 97.2% chance of seeing a sample proportion of 15.2% (or more) of employees failing the course by natural sampling variation if 14.6% is the true population value. b) Even though this program has been shown to be significantly better statistically, why might you not recommend that your company adopt it? O A. You might not recommend that your company adopt the new program because the sample was not chosen at random, thus compromising the results of the O B. You might not recommend that your company adopt the new program because the sample size of the test was not large enough to come to a decision. OC. Under the old methods, 1,402 employees would be expected to fail. With the new program, 1,459 failed. The company would not want to adopt a new program that increases the number of people who fail. OD. Under the old methods, 1,459 employees would be expected to fail. With the new program, 1,402 failed. This is only a decrease of 57 employees. It would depend on the costs of switching to the new program

may developed this program supplied materials and teacher training for a large-scale test involving nearly 9,600 employees in several different sites. Statistical analysis of the results showed that the percentage of employees who did not pass the course was reduced from 15.2% to 14.6%. The hypothesis that the program produced no improvement was rejected with a P-value of 0.028. Complete parts a) and b) below. a) Explain what the P-value means in this context. Choose the correct answer below. O A. There is only a 2.8% chance of seeing a sample proportion of 15.2% (or more) of employees failing the course by natural sampling variation if 14.6% is the true population value. OB. There is only a 2.8% chance of seeing a sample proportion of 14.6% (or less) of employees failing the course by natural sampling variation if 15.2% is the true population value. OC. There is only a 97.2% chance of seeing a sample proportion of 14.6% (or less) of employees failing the course by natural sampling variation if 15.2% is the true population value. O D. There is a 97.2% chance of seeing a sample proportion of 15.2% (or more) of employees failing the course by natural sampling variation if 14.6% is the true population value. b) Even though this program has been shown to be significantly better statistically, why might you not recommend that your company adopt it? O A. You might not recommend that your company adopt the new program because the sample was not chosen at random, thus compromising the results of the O B. You might not recommend that your company adopt the new program because the sample size of the test was not large enough to come to a decision. OC. Under the old methods, 1,402 employees would be expected to fail. With the new program, 1,459 failed. The company would not want to adopt a new program that increases the number of people who fail. OD. Under the old methods, 1,459 employees would be expected to fail. With the new program, 1,402 failed. This is only a decrease of 57 employees. It would depend on the costs of switching to the new program

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.6: Summarizing Categorical Data

Problem 30PPS

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