Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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**Diagram Explanation:**
- The image shows a network with a central component (the "middle hop") connected to various servers and clients.
- Servers (Server-1 to Server-10) are connected to this middle hop, each with a link capacity of \(R_s = 25 \text{ Mbps}\).
- From the middle hop, links extend to each client (Host-1 to Host-10), with these links having a capacity of \(R_c = 50 \text{ Mbps}\).
- The middle hop itself has an aggregate transmission capacity of \(R = 200 \text{ Mbps}\), shared among all server-client pairs.
**Question:**
What is the maximum achievable end-end throughput (in Mbps, give an integer value) for each of the ten client-to-server pairs, assuming that the middle link is fairly shared and all servers are trying to send at their maximum rate?
**Answer Choices:**
- 275 Mbps
- 200 Mbps
- 20 Mbps
- 25 Mbps
- 50 Mbps
To determine the maximum achievable end-to-end throughput for each client-to-server pair, consider the bottleneck in the system:
- The shared middle hop with a capacity of \(R = 200 \text{ Mbps}\) is the limiting factor, as it's shared among all 10 pairs.
- If this total capacity is evenly divided among 10 pairs, each pair would get \(\frac{200 \text{ Mbps}}{10} = 20 \text{ Mbps}\).
Therefore, the correct answer is:
- 20 Mbps](https://content.bartleby.com/qna-images/question/66aa9b8d-2a9a-4598-afb2-640af9accca8/11728593-f0f8-49b5-a540-59eff30c9551/uiibv8_processed.jpeg)
Transcribed Image Text:**Maximum end-end throughput**
Consider the scenario shown below, with 10 different servers (four shown) connected to 10 different clients over ten three-hop paths. The pairs share a common middle hop with a transmission capacity of \(R = 200 \text{ Mbps}\). Each link from a server has to the shared link has a transmission capacity of \(R_s = 25 \text{ Mbps}\). Each link from the shared middle link to a client has a transmission capacity of \(R_c = 50 \text{ Mbps}\).
**Diagram Explanation:**
- The image shows a network with a central component (the "middle hop") connected to various servers and clients.
- Servers (Server-1 to Server-10) are connected to this middle hop, each with a link capacity of \(R_s = 25 \text{ Mbps}\).
- From the middle hop, links extend to each client (Host-1 to Host-10), with these links having a capacity of \(R_c = 50 \text{ Mbps}\).
- The middle hop itself has an aggregate transmission capacity of \(R = 200 \text{ Mbps}\), shared among all server-client pairs.
**Question:**
What is the maximum achievable end-end throughput (in Mbps, give an integer value) for each of the ten client-to-server pairs, assuming that the middle link is fairly shared and all servers are trying to send at their maximum rate?
**Answer Choices:**
- 275 Mbps
- 200 Mbps
- 20 Mbps
- 25 Mbps
- 50 Mbps
To determine the maximum achievable end-to-end throughput for each client-to-server pair, consider the bottleneck in the system:
- The shared middle hop with a capacity of \(R = 200 \text{ Mbps}\) is the limiting factor, as it's shared among all 10 pairs.
- If this total capacity is evenly divided among 10 pairs, each pair would get \(\frac{200 \text{ Mbps}}{10} = 20 \text{ Mbps}\).
Therefore, the correct answer is:
- 20 Mbps
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