
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Problem 5.
Show the first eight words (32 bytes) of the key expansion for a 128-bit key in the following for the AES
The 128-bit key in hexadecimal notation: 000102030405060708090B0A0D0C0F0E
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- QUESTION 9 What is the hexadecimal representation of the memory variable location at address 003FBA03H in the Little Endian format from the 32-bit binary quantity represented by 10100111 110111100101101100001100b? Address in hexadecimal format 003FBA00H 003FBA01H 003FBA02H 003FBA03H 003FBA04H Data in hexadecimal format O a. The hexadecimal representation for the variable located at memory address 003FBA03 is A8. Ob. The hexadecimal representation for the variable located at memory address 003FBA03 is A5. OC. The hexadecimal representation for the variable located at memory address 003FBA03 is A3. Od. The hexadecimal representation for the variable located at memory address 003FBA03 is A7.arrow_forwardDoes the Hamming code follow a particular pattern? Explainarrow_forwardSuppose that we have the following 128-bit AES key, given in hexadecimalrepresentation:54 77 6F 20 4F 6E 65 20 4E 69 6E 65 20 54 77 6F Construct the round key for the first round.arrow_forward
- 1 a. If the last operation performed on a computer with an 8-bit word was an addition in which the two operands were 00000010 and 00000011, what would be the value of the following flags? ● Carry • Zero • Overflow Sign • Even Parity ● Half-Carry b. Repeat for the addition of -1 (twos complement) and +1.arrow_forwardAssemblyarrow_forwardFor AES with a 128 bit block length and a 128-bit key length, what is the output of the first round of AES if the plaintext consists of 128 1's and the first subkey also consists of 128 zeroesarrow_forward
- It is supposed to be in 4 byte, so wouldn't it be (1128879169)₁₀?arrow_forward-128 64 32 -128 1 -128 64 32 0 0 -120--128 16 -128 64 32 1 0 0 (a) An eight-position two's complement value box 16 0 8 16 0 4 8 0 4 0 2 (b) Convert binary 10000011 to decimal 4 0 2 1 +2 2 0 1 8 1 +8 (c) Convert decimal -120 to binary 1 1 +1=-125 1 0arrow_forward
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