Homework Help is Here – Start Your Trial Now!
Math
Advanced Math
Mathematical Problems sidong cunt brick utego (32.1.) Show that the Madhava-Jyesthadeva formula given at the beginning of the chapter is equivalent to or, letting x = tan 6, 0 =(-1* tan24+18 2k + 1 k=0 arctan x= +24+1 2k + 1 (-1)₂ k=0

Mathematical Problems sidong cunt brick utego (32.1.) Show that the Madhava-Jyesthadeva formula given at the beginning of the chapter is equivalent to or, letting x = tan 6, 0 =(-1* tan24+18 2k + 1 k=0 arctan x= +24+1 2k + 1 (-1)₂ k=0

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.3: Trigonometric Functions Of Real Numbers
Problem 48E
See similar textbooks
icon
Related questions
Question
Mathematical Problems sidong cut back (32.1.) Show that the Madhava-Jyesthadeva formula given at the beginning of the chapter is equivalent to or, letting x = tan 0, 0 =(-1) tan24+18 2k + 1 k=0 arctan x= 8 +2k+1 2k + 1 (-1); k=0 DALE
Transcribed Image Text:Mathematical Problems sidong cut back (32.1.) Show that the Madhava-Jyesthadeva formula given at the beginning of the chapter is equivalent to or, letting x = tan 0, 0 =(-1) tan24+18 2k + 1 k=0 arctan x= 8 +2k+1 2k + 1 (-1); k=0 DALE
The product of the given Sine and the radius divided by the Cosine is the first result. From the first,... etc., results obtain...a sequence of results by taking repeatedly the square of the Sine as the multiplier and the square of the Cosine as the divisor. Divide... in order by the odd numbers one, three, etc... From the sum of the odd terms, subtract the sum of the even terms. [The result] becomes the arc. [Rajagopal, 1993, p. 98] These instructions give in words an algorithm that we would write as the following formula, remembering that the Sine and Cosine used in earlier times correspond to our r sine and r cos 0, where r is the radius of the circle: Madhava- A sin³0 3r3 cos³ 0 re Jyesthadeva ² sine formula r cos 0 The bulk of calculus was developed in Europe during the seventeenth century, and it is on that development that the rest of this chapter is focused. 6 sine + 5r5 cos 0
Transcribed Image Text:The product of the given Sine and the radius divided by the Cosine is the first result. From the first,... etc., results obtain...a sequence of results by taking repeatedly the square of the Sine as the multiplier and the square of the Cosine as the divisor. Divide... in order by the odd numbers one, three, etc... From the sum of the odd terms, subtract the sum of the even terms. [The result] becomes the arc. [Rajagopal, 1993, p. 98] These instructions give in words an algorithm that we would write as the following formula, remembering that the Sine and Cosine used in earlier times correspond to our r sine and r cos 0, where r is the radius of the circle: Madhava- A sin³0 3r3 cos³ 0 re Jyesthadeva ² sine formula r cos 0 The bulk of calculus was developed in Europe during the seventeenth century, and it is on that development that the rest of this chapter is focused. 6 sine + 5r5 cos 0
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
SEE MORE TEXTBOOKS