
College Physics
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ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Transcribed Image Text:Math is not required, however you can use it to help with yoursolution.
• You are only required to draw the position of the FINAL IMAGE given the system of lenses
bellow.
Use the following information: Focal length of biconvex lens=25 cm and focal length of the
biconcave length =-10 cm
Object
1.00 m
35 cm
Hint: Find or estimatehow far the image from the lens is from the biconcave lens. Use thatto graph
the optical rays between both lenses to get the FINAL IMAGE.
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- Can you please help with the attached question? Thanks!arrow_forwardAn object is 12.0 cm from a converging lens (focal length = 15.0 cm). Determine the image magnification. Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the magnification is significant.arrow_forwardAn object 4 cm tall is placed in front of the converging lens has a focal length of 10 cm. For each situation below, locate and describe the image (type, orientation, size, and location) using a ray diagramand the lens equations if the object is placed 40 cm from the lens. 30 cm from the lens. 20 cm from the lens 15 cm from the lens 5 cm from the lensarrow_forward
- True statements for optics Which of the following statements for single optic devices are true? Choose all that apply. It turns out that convex lenses always have a positive focal length. For real images, the image distance is negative and the object distance is positive. By convention, an inverted image has a positive image height. A magnification of -2 means the image is magnified. 0 Experiments have shown that converging optics can create virtual images. If an image has a magnification of -8, then the image is virtual. Which must be true? Using a single optic, an image with a negative image height is created. As a result, which of the following MUST be true? Choose all that apply. The image is real The image is virtual The image is inverted The image is upright The image distance is positive The image distance is negative The image has a positive magnification The image has a negative magnification The optic is converging The optic is diverging The optic has a positive focal length…arrow_forwardHelp on three part question on convex images please and thank you.arrow_forwardPhysics Optics: For an infinity optical system, explain why the magnification is determined by the ratio of the focal tube length over the focal objective length. Include a diagram showing the focal tube length and the focal objective.arrow_forward
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