mass of empty cruciole = 31.06ua. mass of Crucible+ Mg= 31.034 t0.001 1) Determine the empirical formula of Mgo based on your data. Follow the steps used in the introduction for finding the empirical formula of NO, (mg) Csl ribbion 6.5o mass of crucible + MqO= 31.970 q t0.0 STEP 1: Find ghåons many grams of Mg were in your MgO sample? (see final results); 31.434-31.644= 0.579 0.002 How many grams dt O in your Mgo sample? This will be a subtraction since you know mass of Mg and mass of Mgo. .57 =0.023 mol (mg) 13369 24.31 STEP 2: Find Motrvert grams of Mg to moles: 6.906 - 0.570.336 31.970 - 31.do4 =6.906 Convert grams of O to moles: 334 Onygen = 0.021 mol 16.60 STEP 3: Find FBivideeach by the smallest number to get a whole number ratio for the formula:
mass of empty cruciole = 31.06ua. mass of Crucible+ Mg= 31.034 t0.001 1) Determine the empirical formula of Mgo based on your data. Follow the steps used in the introduction for finding the empirical formula of NO, (mg) Csl ribbion 6.5o mass of crucible + MqO= 31.970 q t0.0 STEP 1: Find ghåons many grams of Mg were in your MgO sample? (see final results); 31.434-31.644= 0.579 0.002 How many grams dt O in your Mgo sample? This will be a subtraction since you know mass of Mg and mass of Mgo. .57 =0.023 mol (mg) 13369 24.31 STEP 2: Find Motrvert grams of Mg to moles: 6.906 - 0.570.336 31.970 - 31.do4 =6.906 Convert grams of O to moles: 334 Onygen = 0.021 mol 16.60 STEP 3: Find FBivideeach by the smallest number to get a whole number ratio for the formula:
Chapter3: Statistical Tests With Excel
Section: Chapter Questions
Problem 1P
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I'm stuck on step 3. find the formula - Divide each by the smallest number to get while number ratio for the formula
With the information I've provided under attachments can you help?
I don't know how to calculate the smallest number to get the ratio for the formula.
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