Macmillan Learning For a particular reaction, AH = -328.21 kJ/mol and A.S= 98.7 J/(mol-K). Calculate AG for this reaction at 298 K. AG= What can be said about the spontaneity of the reaction at 298 K? The system is spontaneous as written. kJ/mol

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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How can we calculate the reaction and temperature?
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For a particular reaction, AH = -328.21 kJ/mol and AS - 98.7 J/(mol-K).
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Calculate AG for this reaction at 298 K.
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What can be said about the spontaneity of the reaction at 298 K?
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The system is spontaneous as written.
The system is spontaneous in the reverse direction.
The system is at equilibrium.
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Transcribed Image Text:U F5 % 5 For a particular reaction, AH = -328.21 kJ/mol and AS - 98.7 J/(mol-K). = Calculate AG for this reaction at 298 K. A AG= F6 What can be said about the spontaneity of the reaction at 298 K? F 6 The system is spontaneous as written. The system is spontaneous in the reverse direction. The system is at equilibrium. Search F7 & 7 ra F8 * 8 D F9 OP ( 9 F10 *- F11 ) 0 *+ F12 PrtSc + 11 Insert = Resources kJ/mol Delete Backspace G IL
For a particular reaction, AH = 67.7 kJ/mol and AS = 126.9 J/(mol-K). Assuming these values change very little with
temperature, at what temperature does the reaction change from nonspontaneous to spontaneous in the forward direction?
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Is the reaction in the forward direction spontaneous at temperatures greater than or less than the calculated temperature?
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Transcribed Image Text:For a particular reaction, AH = 67.7 kJ/mol and AS = 126.9 J/(mol-K). Assuming these values change very little with temperature, at what temperature does the reaction change from nonspontaneous to spontaneous in the forward direction? o T= Is the reaction in the forward direction spontaneous at temperatures greater than or less than the calculated temperature? Ogreater than less than ▬▬▬ Search 11 8 50 08 F10 *- F11 *+ F12 Resources PrtSc Insert Delete K ► 11 Give
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