Macmillan Learning Dr. Caras was characterizing a cytochrome (an iron containing protein) from a new strain of bacteria. He obtained eight measurements of the percent iron in the protein: 0.5708%, 0.5701%, 0.5692%, 0.5692%, 0.5811%, 0.5695%, 0.5708%, and 0.5698%. Calculate the mean (x) and standard deviation (s) for these results. x = S= Use the Grubbs test to determine if one of these values is an outlier. What is the value of Gcalculated? Gcalculated= % %

Trace metals in drinking water affect the flavor and an unusually high concentration can pose a health hazard. Ten pairs of data were taken measuring zinc concentration in bottom water and surface water. Bottom 0.430 0.266 0.567 0.531 0.707 0.716 0.651 0.589 0.469 0.723 Surface 0.415 0.238 0.390 0.410 0.605 0.609 0.632 0.523 0.411 0.612 With the help of Mathematics and R Studio: Does the data suggest that the true average concentration in the bottom water is different than that of surface water? You can assume that the conditions for inference are met.

If X = 85, Y = 54, and Y' = 62, what is the residual score? a. -8 b. 23 c. 8 d. 31

In the General Social Survey, respondents were asked whether they favor cuts in governmental spending. Here is the output summarizing this variable: Statistics CUTS IN GOVT SPENDING. Valid 1375 Missing 1492 Mean 2.24 Median 2.00 Mode Percentiles 25 1.00 50 2.00 75 3.00 CUTS IN GOVT SPENDING. Cumulative Frequency Percent Valid Percent Percent Valid STRONGLY IN FAVOR 413 14.4 30.0 30.0 IN FAVOR 471 16.4 34.3 64.3 NEITHER 294 10.3 21.4 85.7 AGAINST 143 5.0 10.4 96.1 STRONGLY AGAINST 54 1.9 3.9 100.0 Total 1375 48.0 100.0 Missing JAP 1477 51.5 DK 7 .2 NA 8 3 Total 1492 52.0 Total 2867 100.0 Which of the following is TRUE for this variable? The median is 2 The mean is not appropriate for this variable The mean is 2.24 V The median is IN FAVOR The mode is IN FAVOR The mode is 2 O The median is not appropriate for this variable

rength of concrete: The compressive strength, in kilopascals, was measured for concrete blocks from five different batches of concrete, both three and six days after pouring. The data are as follows. Can you conclude that the mean strength after three days differs from the mean strength after six days? Let H, represent the mean strength after three days and P =H, -P. Use the a=0.01 level and the P-value method with the TI-84 Plus calculator. Block 1 4 After 3 days 1317 1363 1321 1333 1311 After 6 days 1382 1341 1327 1342 1386 Send data to Excel Part 1 of 4 (a) State the null and alternate hypotheses. H: This hypothesis test is a (Choose one) v test. Part 2 of 4 (b) Compute the P-value. Round the answer to at least four decimal places. P-value = Part 3 of 4 Determine whether to reject Ho. (Choose one) v the null hypothesis. Part 4 of 4 (c) State a conclusion. There (Choose one) v enough evidence to conclude that the mean strength after three days differs from the mean strength after six…

Suppose u, and u, are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 5, x = 115.1, s, = 5.05, n = 5, y = 129.2, and s, = 5.36. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) n USE SALT Does the interval suggest that precise information about the value of this difference is available? O Because the interval is so narrow, it appears that precise information is available. o Because the interval is so wide, it appears that precise information is not available. o Because the interval is so narrow, it appears that precise information is not available. Because the interval is so wide, it appears that precise information is available. You may need to use the appropriate table in the Appendix of Tables to answer this question.

Suppose the correlation coefficient r=0.16 Find:a. The coefficient of determination r2=  (round to 3 decimal places)b. The percentage of explained variation = % (round to 1 decimal place)c. The percentage of unexplained variation = % (round to 1 decimal place)

Suppose u1 and uz are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 6, x = 115.6, s1 = 5.03, n = 6, y = 129.9, and s2 = 5.38. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) In USE SALT Does the interval suggest that precise information about the value of this difference is available? Because the interval is so narrow, it appears that precise information is available. Because the interval is so narrow, it appears that precise information is not available. o Because the interval is so wide, it appears that precise information is not available. o Because the interval is so wide, it appears that precise information is available.

Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 134 to 192 cm and weights of 40 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 166.94 cm, y = 81.26 kg, r= 0.352, P-value = 0.000, and y = - 101 + 1.04x. Find %3D the best predicted value of y (weight) given an adult male who is 145 cm tall. Use a 0.10 significance level. The best predicted value of y for an adult male who is 145 cm tall is kg. (Round to two decimal places as needed.)

Trace metals in drinking water affect the flavor and an unusually high concentration can pose a health hazard. Ten pairs of data were taken measuring zinc concentration in bottom water and surface water. Bottom 0.430 0.266 0.567 0.531 0.707 0.716 0.651 0.589 0.469 0.723 Surface 0.415 0.238 0.390 0.410 0.605 0.609 0.632 0.523 0.411 0.612 Does the data suggest that the true average concentration in the bottom water is different than that of surface water? Note: You can assume that the conditions for inference are met.