MOHWaOHCOMEONOBHY →MeOH (solvent)Na₂Cr₂O7+H₂SO4 + H₂O-H1. CH3 Li2. H30OCH31. 2 CH3CH₂ CH₂Li.2. H30+

NaBH4 reduces aldehyde or ketone to alcohol but does not reduce esterNa2Cr2O7 in acidic medium…

Answered: м OH Ма OH OME NaBHч Meон (solvent)…

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м OH Ма OH OME NaBHч Meон (solvent) NazCrzOr+HzSO4 + H2O> H 1. CH3 Li 2. Н30+ Я ОСН3 1. 2 H3 Hz CHzli 2. Н30+

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

M
OH
Wa
OH
COME
O
NOBHY →
MeOH (solvent)
Na₂Cr₂O7+H₂SO4 + H₂O
-H
1. CH3 Li
2. H30
OCH3
1. 2 CH3CH₂ CH₂Li.
2. H30+

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