m 100 kg 1 m

Q: A block having a mass of 0.7 kg is at rest near the edge of a frictionless table 1.6 m high. A…

A:

Q: partially filled one-gallon [gal] pitcher, that has a mass of 0.35 kilograms [kg] when empty, is…

A: Acceleration of an object is given by force applied dividided by its mass .

Q: (owo) and the inertia tensor I given as shown, the magnitude of the angular Momentum is equal to: *…

A: Given, ω= 0ω0 Inertia tensor, I =ma2 130-140230-14013

Q: A pendulum is 0.280 m long, and the bob has a mass of 1.00 kg. At the bottom of its swing, the bob's…

A: A pendulum swing can be considered as a small part of vertical rotation. Therefore, other than…

Q: An Object with a mass of 6.2 kg accelerates 12.3 m/s2 when an unknown force is applied to it. What…

A: Given value--- mass = 6.2 kg. acceleration = 12.3 m/s2  . We have to find--- force ?

Q: The same rocket sled drawn in the figure is decelerated at a rate of 191 m/s². What force (in N) is…

A: Given:  mass, m = 2050 kg  acceleration, a = 191 m/s2

Q: 42. A car of mass 1000kg travelling along a straight path accelerates uniformly from 15m/s to 25m/s…

A: 42. Given: Mass of car, m=1000 kg Initial speed, u=15 m/s Final speed, v=25 m/s Distance, d=320 m…

Q: Two blocks A and B of the same mass 1.16 kg are released from rest on a 29° incline when they are S…

A: The free body diagram for block A is given below.

Q: A car traveling at 20 m/s runs into a bridge abutment and crumples for 1.2 m before coming to a full…

A: Given: The intial speed of the car is 20 m/s. The distance traveled by car is 1.2 m. The final speed…

Q: 1. A person is standing on a building with a height h. His mass is m and acceleration due to gravity…

A: From the question, it is given that- Height of building = h Initial speed of person: u = 0 m/s Mass…

Q: A mass of 1.33 kg is initially at rest upon a frictionless incline of 57 degrees. How far down the…

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Q: Four arrows, all with the same shape and size, are shot directly upward. Ignore the effect of air…

A: According to the Newton's laws of motion , the maximum vertical height is calculated  by using the…

Q: A net force of 81.6 N propels a 4.00-kg model rocket. After being launched from rest, how fast is…

A: Dear student We can apply the equation of motion when acceleration is constant. Which is as : V = u…

Q: A.) Using the alternate form of Newton's second law, compute the force (in N) needed to accelerate a…

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Q: An object with a mass of 2.0 kg is dropped and takes 3.0 s to hit the ground. Then another object…

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Q: In a Subaru TV commercial, a dog is driving a car of total MASS 1,812 kg.  Suddenly a person runs…

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Q: A mobile is constructed of light rods, light strings, and beach souvenirs as shown in the figure…

A: Given, m4=12.0gd1=3.40cmd2=5.30cmd3=2.10cmd4=5.40 cmd5=2.10cmd6=2.60cm

Q: mass m  is pulled H=0.5 (M) and released as shown in the figure. How many kilograms should the mass…

A: From the energy conservation, Substitute h=0.5 m.

Q: Two blocks A and B of the same mass 1.03 kg are released from rest on a 29.6° incline when they are…

A: Consider the given data as below. Mass of block A and B, mA=mB=m=1.03 kg The coefficient of friction…

Q: I was told that if an equal amount (same mass, velocity, time interval) of non bouncy and bouncy…

A: Given:-  I was told that if an equal amount (same mass, velocity, time interval) of nonbouncy and…

Q: A particle of mass 2.5kg moves according to the equation x(t)=10t?, where x is in meters and t is in…

A: Given The mass of the particle is m = 2.5 kg. The equation for the distance is x(t) = 10t2. The…

Q: Two weights, each weighing m, are hung over a pulley. If an additional weight of 100 g is attached…

A: Here given two weights each are weighing m. They are hanged from a pully. There is an additional…

Q: The 100 kg block in the figure takes 5.6 s to reach the floor after being released from rest.(Figure…

A: Known mass, Time taken by the 100kg block to reach the floor, Distance covered by the 100kg block…

Q: A 2.00 kg stone is sliding to the right on a frictionless horizontal surface at 5.00 m/s when it is…

A: 6.25m/s3.75m/sAlso find the detailed solution of the problemExplanation:Detailed explanation:

Q: two blocks are attached together with a piece of string. Block #1 has a mass of 3 kilograms and…

A: Consider the free-body diagram of both the blocks as follows.

Q: A 950-kg car pulls a boat on a trailer. (a) What force resists the motion of the car, boat, and…

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Q: A child pushes a cart with a force of 14.5 N over a distance of 2.25 m. If the cart has a mass of 18…

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Q: A boxer punches a punching bag. The time of impact of the glove and the bag is 0.01 s and the mass…

A: Average force acting on the glove is given by change in momentum per time. So  F=(m1v1-m2v2)/t…

Q: In the district soccer championship finals, Elizabeth kicks a 0.96 kg soccer ball with a force of…

A: Mass of the soccer ball, m = 0.96 kg Force applied, F = 28.6 N   From Newton's second law of motion,…

Q: An  Atwood's machine with a frictionless pulley has mass1 = 7 kg and is accelerating up at 6 m/s2.…

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Q: A block having a mass of 0.7 kg is at rest near the edge of a frictionless table 1.1 m high. A…

A:

Q: A 2000kg elevator has a downward acceleration of 1.0 m/s/s. (a) What is the tension in its…

A: (a)   M=2000 kg Force due to gravity = Mg=2000*10=20000 N T= tension  a= acceleration   Ma=Mg-T…

Q: A raw egg with a mass of .07 kg is dropped without a protective device from 3 heights: a) 1 meter…

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Q: When the three blocks in the figure below are released from rest, they accelerate with a magnitude…

A: see handwritten below

Q: A young girl is riding a bicycle that has a total mass (including the kid) of 21.2 kg. The girl is…

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Q: The force on an object moving through a viscous fluid (like honey) is F = -bv, where v is the speed…

A: Given data:  Force on an object F = -bv Here, v = speed of the object Required: SI unit of b

Q: A net force is applied in the positive directions to an object moving in one dimension. The graph of…

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Q: Section 1.6 30. a. With what initial speed must you throw a ball vertically for it to reach a height…

A: Height h=20 ft = 6.09 m

Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows: