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Transcribed Image Text:Two constant forces act on a 5.00-kg object moving in the xy-plane, as
42.0 N at 150°. At
shown in the figure below. Force F1 is 25.0N at 35.0°, while F2
time t = 0, the object is at the origin and has velocity v; = (4.0 i+2.5 j) m/s. Express
all of your answers for this problem with the correct number of significant
figures.
F2
F1
150°
35.0°
(a)
Express F1 and F2 in unit-vector (component) notation.
(b)
press both the net force vector and the acceleration vector in component form
and magnitude-angle form.
Find the net force on and the acceleration of the object. Ex-
![Find the object's velocity and position at t = 3.00 s. Express both
(c)
the velocity vector and the position vector in component form and magnitude-angle
form. [Note: Don't forget to treat the x and y motion independently!]
At t = 3.00 s, find the change in the object's kinetic energy two ways:
(d)
i) using AK = m(v; – v?)/2, and ii) using W = F. d.](https://content.bartleby.com/qna-images/question/859743d5-9578-4a68-94b4-09f68a5c3500/a6a838a2-6e8e-40c7-a380-4991222b999b/wgkp18_processed.png)
Transcribed Image Text:Find the object's velocity and position at t = 3.00 s. Express both
(c)
the velocity vector and the position vector in component form and magnitude-angle
form. [Note: Don't forget to treat the x and y motion independently!]
At t = 3.00 s, find the change in the object's kinetic energy two ways:
(d)
i) using AK = m(v; – v?)/2, and ii) using W = F. d.
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