Lucy loves to play the Hop, Skip and Jump game. Given an N*M matrix and starting from cell (1,1), her challenge is to hop in an anti- clockwise direction and skip alternate cells. The goal is to find out the last cell she would hop onto. Write an algorithm to find the last cell Lucy would hop onto after moving anti-clockwise and skipping alternate cells. Input The first line of input consists of two integers- matrix row and matrix col, representing the number of rows (N) and the number of columns (M) in the matrix, respectively. The next M lines consist of N space-separated integers representing the elements in each cell of the matrix. Output Print an integer representing the last cell Lucy would hop onto after following the given instructions.
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- Write a program that inputs a matrix and displays the trans- pose of that matrix. A transpose of a matrix is obtained by converting all the rows of a given matrix into columns and vice versa.Consider an n by n matrix, where each of the n2 entries is a positive integer. If the entries in this matrix are unsorted, then determining whether a target number t appears in the matrix can only be done by searching through each of the n2 entries. Thus, any search algorithm has a running time of O(n²). However, suppose you know that this n by n matrix satisfies the following properties: • Integers in each row increase from left to right. • Integers in each column increase from top to bottom. An example of such a matrix is presented below, for n=5. 4 7 11 15 2 5 8 12 19 3 6 9 16 22 10 13 14 17 24 1 18 21 23 | 26 | 30 Here is a bold claim: if the n by n matrix satisfies these two properties, then there exists an O(n) algorithm to determine whether a target number t appears in this matrix. Determine whether this statement is TRUE or FALSE. If the statement is TRUE, describe your algorithm and explain why your algorithm runs in O(n) time. If the statement is FALSE, clearly explain why no…Write a program that can inverse a matrix by using an approach to find its minor, cofactor and adjugate matrix. Test your program with the given matrix ?
- Construct a square matrix with NN rows and NN columns consisting of nonnegative integers from 00 to 10^{18}1018, such that its determinant is equal to 11, and there are exactly A_iAi odd numbers in the ii-th row for each ii from 11 to NN, or report there isn't such a matrix. Standard input The first line contains a single integer NN. Each of the next NN lines contains a single integer A_iAi. Standard output If there is no solution, output \text{-}1-1. Otherwise, print NN lines, each consisting of NN integers, representing the values of the constructed matrix. If there are multiple solutions, print any. Constraints and notes 2 \le N \le 502≤N≤50 1 \leq A_i \leq N1≤Ai≤N For 40\%40% of the test files, N \le 17N≤17.Compute the code that return the matrix M = AT A for a given matrix A - the superscript T denoted the transpose. I have started the code for you, which gets the dimension of the matrix, and creates the zero matrix of the correct size. I have also provided some of the loops involved. : # perform and return the multiplication of $A^TA$ import numpy as np def multiply_At_A(A): # these lines set up the correct dimensions #of the returned matrix. # the matrix A is of dimension diml dim2 - # the matrix A^T (transpose of A) is dim2 x diml # the matrix (A^T A) is of dimension dim2 x dim2 dim1 = A. shape [0] dim2 = A. shape [1] matrix = np.zeros([dim2, dim2]) for i in range (dim2): for j in range (dim2): # complete the final loop to #compute matrix[i,j] # YOUR CODE HERE return matrixHi I need help writing a java program that implements Prim's algorithm. The imput of the program is given by the scanner with an undirected graph. First input line is the number of vertices, second input is the number of undirected edges. After that the input is a matrix of 3 by the number of undirected edges. The matrix firt 2 column contain the end points and the third column contains the weight . The output of the program is an integer representing the sum of all the edges that make up the minimum spanning tre. I have attach a picture for farther details. THANKS
- In Python, generate a random matrix A with 100 entries each of which is an independent numberpseudo-randomly drawn (uniformly) from the interval (0, 1). Let B = A + AT . Use Python to calculatethe diagonal matrix D with the same eigenvalues as B. Then use the QR method to block-diagonalize Bover R. Do at least 100 steps of the QR switching. You should end up with a matrix E which is differentthan D. Answer the question of why.Implement a program that will populate a 6x5 matrix with randomly generated integers from 100 to 500. (1) print your matrix in a table form. (2) modify your code to multiply all odd numbers by 2 and print the matrix. Sample run: Initial Matrix: 145 | 437 | 222 | 101 | 100 | 278 500 | 190 | 415 | 288 | 466 322 377 | 240 | 451 | 331 186 186 432 102 | 106 | 105 249 248 | 117 | 213 | 499 488 355 | 266 | 396 | New Matrix: 290 | 874 | 222 | 101 | 100 | 278 500 | 190 | 830 288 | 466 322 754 | 240 | 902 | 662 186 432 | 102 | 106 | 210| 498 248 | 234 | 426 | 998 488 710 | 266 | 396 |Write a program to read a matrix of size m × n and print its transpose. Please explain your code clealry and print the output
- 4x1+4x2+6x3+9x4=03x1+3x5=26x2+5x4+7x5=-46x1+8x4+2x5=54x5+7x2+6x3+8x1=-10Represent the set of equations in a matrix equation, Ax=b, where A is a square matrix and x and b are column vectors. Write the line of code to define matrix A for this problem matlab/octave languageCompute the code that return the matrix M = AT A for a given matrix A - the superscript T denoted the transpose. I have started the code for you, which gets the dimension of the matrix, and creates the zero matrix of the correct size. I have also provided some of the loops involved. # perform and return the multiplication of $A TAS import numpy as np def multiply_At_A(A): # these lines set up the correct dimensions of the returned matrix. # the matrix A is of dimension dim1 x dim2 - # the matrix A^T (transpose of A) is dim2 x diml # the matrix (A^T A) is of dimension dim2 x dim2 dim1= A.shape [0] dim2 = A.shape [1] matrix = np.zeros( [dim2, dim2]) for i in range (dim2): for j in range (dim2): # complete the fi # YOUR CODE HERE return matrix loop to compute matrix [i,.Write a program to create a matrix A(5*5), then replace the diagonal with zeros. Add “break” or “continue” when it is suitable. used matlab