Light with a wavelength of 646 nm passes through two slits and forms an interference pattern on a screen 8.75 m away. The distance between the two second-order bright fringe is 10.32 cm. What will be the distance between the central bright fringe and the third-order minimum?

Light is sent through a single slit of width w = 0.52 mm. On a screen, which is L = 1.9 m from the slit, the width of the central maximum is D = 5.2 mm. a) The angle of the first dark fringe theta dark. Express sin(theta dark) in terms of the wavelength of the light λ and w. sin(theta dark) =  b) Express tan(theta dark) in terms of D and L. c) If D << L, how is tan(theta dark) related to sin(theta dark)? d) Express λ in terms of w, D, and L? e) Solve for the numerical value of λ, in nanometers.

Using a 685 nm wavelength laser, you form the diffraction pattern of a 1.01 mm wide slit on a screen. You measure on the screen that the 15th dark fringe is 9.23 cm away from the center of the central maximum. How far is the screen located from the slit?

Using a 697 nm wavelength laser, you form the diffraction pattern of a 1.11 mm wide slit on a screen. You measure on the screen that the 11th dark fringe is 8.33 cm away from the center of the central maximum. How far is the screen located from the slit?