Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Question
Light from an ideal spherical blackbody 15.0 cm in diameter
is analyzed by using a diffraction grating that has 3850 lines/cm.
When you shine this light through the grating, you observe that the
peak-intensity wavelength forms a first-order bright fringe at +-14.4
from the central bright fringe. (a) What is the temperature of the blackbody?
(b) How long will it take this sphere to radiate 12.0 MJ of energy
at constant temperature?
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- Please explain with steps.arrow_forwardExplain the blackbody radiation and its effect?arrow_forwardYou have stated that the convective area is πr^2. Please explain this. πr^2 is the area for a circle, not a sphere. It should be 4πr^2 as this is equal to the surface area of the sphere as you have done correctly in the radiative area. A conv= 4πr^2*3*293-292 = 0.377 A rad = 4πr^2*0.2*5.67x10^-8*(292^4-291^4) = 0.144 I have tried to multiply the convective area by 4πr^2 instead of πr^2 but it is giving me an incorrect total heat transfer rate of 0.377+0.144 = 0.521 the correct answer is supposed to be 0.236arrow_forward
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