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Let's say we're in a proof and we know: (∀d)(S(d)→R(c,d))→(∀d)(M(d)→R(c,d)) Suppose we wanted to do universal instantiation, substituting scrat for the d's bounded by the first (leftmost) occurrence of (∀d). What is the result of this substitution? Group of answer choices (S(scrat)→R(c,scrat))→(∀d)(M(d)→R(c,d)) (S(scrat)→R(c,scrat))→(M(scrat)→R(c,scrat)) S(scrat)→R(c,scrat) (∀d)(S(d)→R(c,d)→(M(d)→R(c,d)))     2. In a proof, which of the following lines "push the stack?" (I.e., add to the number of vertical lines on the left-hand-side?) Group of answer choices Let n be an arbitrary natural number. Since a

Let's say we're in a proof and we know: (∀d)(S(d)→R(c,d))→(∀d)(M(d)→R(c,d)) Suppose we wanted to do universal instantiation, substituting scrat for the d's bounded by the first (leftmost) occurrence of (∀d). What is the result of this substitution? Group of answer choices (S(scrat)→R(c,scrat))→(∀d)(M(d)→R(c,d)) (S(scrat)→R(c,scrat))→(M(scrat)→R(c,scrat)) S(scrat)→R(c,scrat) (∀d)(S(d)→R(c,d)→(M(d)→R(c,d)))     2. In a proof, which of the following lines "push the stack?" (I.e., add to the number of vertical lines on the left-hand-side?) Group of answer choices Let n be an arbitrary natural number. Since a

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 54E
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Let's say we're in a proof and we know:

(∀d)(S(d)→R(c,d))→(∀d)(M(d)→R(c,d))

Suppose we wanted to do universal instantiation, substituting scrat for the d's bounded by the first (leftmost) occurrence of (∀d). What is the result of this substitution?

Group of answer choices

(S(scrat)→R(c,scrat))→(∀d)(M(d)→R(c,d))

(S(scrat)→R(c,scrat))→(M(scrat)→R(c,scrat))

S(scrat)→R(c,scrat)

(∀d)(S(d)→R(c,d)→(M(d)→R(c,d)))

 
 
2. In a proof, which of the following lines "push the stack?" (I.e., add to the number of vertical lines on the left-hand-side?)
Group of answer choices

Let n be an arbitrary natural number.

Since a<b and a<b→0<c2, we can conclude 0<c2.

Assume a<b.

Since (∀c)R(c,c), R(e,e).

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