Let's consider a snowplow which is scooping up snow 2 cm deep (d) and the blade is 1 m wide. Lets assume the specific gravity (SG) of snow is 0.2. If we want to plow at 55 km/hr and a 30 degree vertical angle of discharge: (a) what is the force exerted on the blade? (just treat the snow like a fluid of density 200 kg/m^3). (b) what is the power necessary? (c) Suppose with the 30 degree vertical angle of discharge would this change the force exerted on the blade? what would it be if it changes? (It might occur to you that it does little good if we don't angle the blade as we just throw the snow in front of the truck...still in the roadway..)

A person, not in the system, drags a heavy box across a level floor. What is the energy conservation equation?

Solve it as much as you can

A jet impinges on a splitter block. The incoming jet is horizontal and has a flow rate of Q1 = 8000 cm³/s and a cross-sectional area of A1 = 40 cm². The block splits the jet in to two smaller jets. One is deflected upward by 45°, and has a flow rate of Q2 = 6000 cm3/s and a cross-sectional area of A, = 30 cm?. The other jet is deflected downward by 45°, and has a flow rate of Q3 = 2000 cm³/s and a cross-sectional area of A3 = 10 cm². You may assume that the pressure everywhere is equal to atmospheric pressure, and the density of the fluid is 1000 kg/m³. Find the horizontal momentum flux in, or in Q,= 6000 cm³/ A2= 30 cm2 Q,= 8000 cm³/s . %3D e = 45° e = 45° A,= 40 cm² %3D A3= 10 cm² Q3= 2000 cm3/s