Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Round your answers to four decimal places.) (a) P(0 sz$2.23) (b) P(0 sz s 2) (c) P(-2.10 sz≤ 0) (d) A(-2.10 sz≤ 2.10) (e) P(Z 1.86) USE SALT (f) P(-1.85 s2) (g) P(-1.10 sz≤ 2.00) (h) P(1.86 sz≤ 2.50) (1) P(1.102) (1) P(1Z1 ≤ 2.50)

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Logan and Brian began arguing about who did better on their tests, but they couldn't decide who did better given that they took different tests. Logan took a test in Art History and earned a 76.8, and Brian took a test in English and earned a 68.9. Use the fact that all the students' test grades in the Art History class had a mean of 71.9 and a standard deviation of 11.6, and all the students' test grades in English had a mean of 61 and a standard deviation of 9.4 to answer the following questions.a) Calculate the z-score for Logan's test grade.z=z= [Round your answer to two decimal places.] b) Calculate the z-score for Brian's test grade.z=z= [Round your answer to two decimal places.]c) Which person did relatively better? Logan Brian They did equally well.

q19- If X and Y are random variables with E(X) =98.5 and E(Y) = 60.4, then E(3X + 4Y) is: a. 537.10 b. 268.55 c. 805.65 d. 1074.20