I need help Let y = f(x) be an positive increasing function defined for x > 0. The length of the curvedescribed by the graph of y = f(x) between xO and x = t is equal to|3D1tv4+t? + ln(t + v4+t?) – In 2If the tangent line to such a curve at æ = 4 is y = mx + c, then find m.(Enter an integer)m =

Given: Length of curve y=f(x) is between x=0 and x=t is equal to14t4+t2+lnt+4+t2−ln2.

Let y = f(x) be an positive increasing function defined for x > 0. The length of the curve described by the graph of y = f(x) between x = 0 and x = t is equal to 1 tVA+* +In(t + v/4+P) – In 2 tv4+t? 4 If the tangent line to such a curve at ¤ = 4 is y = mx + c, then find m.

Let y = f(x) be an positive increasing function defined for x > 0. The length of the curve described by the graph of y = f(x) between x = 0 and x = t is equal to 1 tVA+* +In(t + v/4+P) – In 2 tv4+t? 4 If the tangent line to such a curve at ¤ = 4 is y = mx + c, then find m.

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter7: Integration

Section7.1: Antiderivatives

Problem 45E

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I need help

Let y = f(x) be an positive increasing function defined for x > 0. The length of the curve
described by the graph of y = f(x) between x
O and x = t is equal to
|3D
1
tv4+t? + ln(t + v4+t?) – In 2
If the tangent line to such a curve at æ = 4 is y = mx + c, then find m.
(Enter an integer)
m =

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$\begin{array}{l} Length of curve y = f (x) is between x = 0 and x = t is equal to \\ \frac{1}{4} t \sqrt{4 + t^{2}} + \ln (t + \sqrt{4 + t^{2}}) - \ln 2. \end{array}$

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