A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN: 9780134753119
Author: Sheldon Ross
Publisher: PEARSON
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Please solve (a) & (b) only! Thanks.

Let \( X_1, X_2, \) and \( X_3 \) represent the times necessary to perform three successive repair tasks at a certain service facility. Suppose they are independent, normal r.v’s with expected values \( \mu_1, \mu_2, \) and \( \mu_3 \) and variances \( \sigma_1^2, \sigma_2^2, \) and \( \sigma_3^2 \) respectively. (Round your answers to four decimal places.)

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### (a)

If \( \mu_1 = \mu_2 = \mu_3 = 70 \) and \( \sigma_1^2 = \sigma_2^2 = \sigma_3^2 = 18 \), calculate \( P(T_0 \le 228) \) and \( P(174 \le T_0 \le 228) \).

- \( P(T_0 \le 228) = \) \(\underline{\hspace{2cm}}\)
- \( P(174 \le T_0 \le 228) = \) \(\underline{\hspace{2cm}}\)

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### (b)

Using the \( \mu_i \)’s and \( \sigma_i^2 \)’s given in part (a), calculate both \( P(64 \le \overline{X} \)) and \( P(68 \le \overline{X} \le 72) \).

- \( P(64 \le \overline{X}) = \) \(\underline{\hspace{2cm}}\)
- \( P(68 \le \overline{X} \le 72) = \) \(\underline{\hspace{2cm}}\)

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### (c)

Using the \( \mu_i \)’s and \( \sigma_i^2 \)’s given in part (a), calculate \( P(-12 \le X_1 - 0.5X_2 - 0.5X_3 \le 6) \).

- \( P(-12 \le X_1 - 0.5X_2 - 0.5X_3 \le 6) = \) \(\underline{\hspace{2cm}}\)

#### Interpret the quantity \( X_1 - 0.5X_2 - 0.5
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Transcribed Image Text:Let \( X_1, X_2, \) and \( X_3 \) represent the times necessary to perform three successive repair tasks at a certain service facility. Suppose they are independent, normal r.v’s with expected values \( \mu_1, \mu_2, \) and \( \mu_3 \) and variances \( \sigma_1^2, \sigma_2^2, \) and \( \sigma_3^2 \) respectively. (Round your answers to four decimal places.) --- ### (a) If \( \mu_1 = \mu_2 = \mu_3 = 70 \) and \( \sigma_1^2 = \sigma_2^2 = \sigma_3^2 = 18 \), calculate \( P(T_0 \le 228) \) and \( P(174 \le T_0 \le 228) \). - \( P(T_0 \le 228) = \) \(\underline{\hspace{2cm}}\) - \( P(174 \le T_0 \le 228) = \) \(\underline{\hspace{2cm}}\) --- ### (b) Using the \( \mu_i \)’s and \( \sigma_i^2 \)’s given in part (a), calculate both \( P(64 \le \overline{X} \)) and \( P(68 \le \overline{X} \le 72) \). - \( P(64 \le \overline{X}) = \) \(\underline{\hspace{2cm}}\) - \( P(68 \le \overline{X} \le 72) = \) \(\underline{\hspace{2cm}}\) --- ### (c) Using the \( \mu_i \)’s and \( \sigma_i^2 \)’s given in part (a), calculate \( P(-12 \le X_1 - 0.5X_2 - 0.5X_3 \le 6) \). - \( P(-12 \le X_1 - 0.5X_2 - 0.5X_3 \le 6) = \) \(\underline{\hspace{2cm}}\) #### Interpret the quantity \( X_1 - 0.5X_2 - 0.5
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