Let x be a continuous random variable with a standard normal distribution. a) Using the accompanying standard normal distribution table, find P(– 1.89 sxs1.89). b) What percentage of the area is from - 1.89 to 1.89? Click the icon to view the standard normal distribution table. a) P(- 1.89 sxs1.89) = (Round to four decimal places as needed.)

Use the normal distribution of SAT critical reading scores for which the mean is 501501 and the standard deviation is 113113. Assume the variable x is normally distributed. left parenthesis a right parenthesis(a) What percent of the SAT verbal scores are less than 550550​? left parenthesis b right parenthesis(b) If 1000 SAT verbal scores are randomly​ selected, about how many would you expect to be greater than 525525​?

Find the  value to the left of the mean so that 99.13% of the area under the distribution curve lies to the right of it. Use The Standard Normal Distribution Table and enter the answer to 2 decimal places. z=

Find the area under the standard normal distribution curve to the left of  =z−1.08 . Use The Standard Normal Distribution Table and enter the answer to  4  decimal places.     The area to the left of the  z  value is    .     ???

Just need part d.

Find the area under the standard normal distribution curve

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Find the area of the shaded region. The graph depicts the standard normal distribution with mean O and standard deviation 1. Click to view page 1 of the table. Click to view page 2 of the table. The area of the shaded region is (Round to four decimal places as needed.) z = 0.83