Let V=R². For (u1, U2), (v₁, v2) € V and a € R define vector addition by (u₁, u₂) E (v₁, v2) := (u₁ + v₁ +2, u2+ v2-2) and scala multiplication by a □ (u₁, u2) = (au₁+2a-2, au2 - 2a + 2). It can be shown that (V,B,D) is a vector space over the scalar field R the following: the sum: (4,8) (1,-6)=( the scalar multiple: 10 (4,8) = the zero vector: or=d) the additive inverse of (x, y): 00 B(x, y) =(

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