Let us revisit the hypothetical study discussed earlier in the section in which consumers are asked to rate a company both before and after viewing a video on the company twice a day for a week. Use an alpha of 0.05 to test to determine whether there is a significant increase in the rating of the company after the 0ne-week video treatment. Assume that difference in ratings are normally distributed in the population. # 1 2 3 4 5 6 7 Before 32 11 21 17 30 38 14 After 39 15 35 13 41 39 22

Question 3 The number of hours worked per week for a sample of ten students is shown below. Student Hours 1 39 28 10 16 26 34 38 9. 4 10 32 1. Determine the mean, median, and mode. 2. What is the range of the data for the hours worked? 3. What is the standard deviation for the number of hours worked? 2. 3. 4, 7, 8.

please answer question 2

Consider the following data: −10, −10, 0, 3, −10, 3, 3  Step 1 of 3: Calculate the value of the sample Variance. Round your answer to one decimal place. Step 2 of 3: Calculate the value of the sample deviation. Round your answer to one decimal place. Step 3 of 3: Calculate the value of the range.

The data is as follows: 2 0's, 6 1's, 10 2's, 32 3's, 50 4's, 69 5's, 50 6's, 38 7's, 19 8's, 12 9's, and 4 10's.

Do question iii and iv only.

Below are the number of questions answered correctly by 14 students in a Data Management class on an exam with forty questions.           16  20  22  26  26  27  29  32  34  36  36  37  38  39 What percentile is the student who scored 32?

EXAMPLE 4.9 Students who seek therapy at university counseling centers often do not attend many sessions. For example, in one study, the median number of therapy sessions was 3 and the mean was 4.6 (Hatchett, 2003). Let’s examine the spread of fictional scores for a sample of five students: 1, 2, 4, 4, and 10 therapy sessions, with a mean of 4.2. We find out how far each score deviates from the mean by subtracting the mean from every score. First, we label with an X the column that lists the scores. Here, the second column includes the results we get when we subtract the mean from each score, or X − M. We call each of these a deviation from the mean (or just a deviation)—the amount that a score in a sample differs from the mean of the sample. X X − M   1 − 3.2   2 − 2.2   4 − 0.2   4 − 0.2 10     5.8 But we can’t just take the mean of the deviations. If we do (and if you try this, don’t forget the signs—negative and positive), we get 0—every time. Are you surprised?…

QUESTION 2 The following sample of 50 was selected randomly from a large population. Match the following questions with their answers: 3 16 55 75 91 5 16 58 78 92 9 19 60 81 93 9 20 62 84 93 10 20 67 86 93 13 22 72 86 94 15 34 73 86 94 15 37 74 94 16 49 74 94 16 51 75 94 56.72 32.92 Approximately what percent of data is more than the 90th mean st dev 8888 87 87 89 A. 48%

Do question i and ii only.