Let u = cos(4x) and du = e² da, then by using IBP, the integral [e²= cos(4x) e2x cos(4x) dx is equal to 0 121 122 cos(4x) - 2 [₁ S e²* sin(4x) dx 2e²= cos(4x) - 1²/2 e²* sin(4x) dx e²x cos(4x) + 2 e²* sin(4x) dx 1 e²* sin(4x) dx 2x 2 ܩܕܟܟ 0 1 2e²* cos(4x) +

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