SOLVE BOTH PLEASE!!! the cirlced one 6+----and v=- 1Let u =6Show thatakHow can it be shown that a vector b is in Span {u, v}?Let b =is in Span {u, v} for all a and k.A. Determine if the system containing u, v, and b is consistent. If the system is consistent, then b is in Span {u, v}.aAB. Determine if the system containing u, v, and b is consistent. If the system is consistent, b might be inSpan {u, v}.C. Determine if the system containing u, v, and b is consistent. If the system is consistent, then b is not inSpan {u, v}.D. Determine if the system containing u, v, and b is consistent. If the system is inconsistent, then b is inSpan {u, v}.Find the augmented matrix u v bb]. Let A =1 0 -603-5-59 4and b =9-2. Denote the columns of A by a₁, a2, a3, and let W = Span {a₁, a2, ª3}.- 29a. Is b in {a₁, a₂, a3}? How many vectors are in {a₁, a2, a3}?b. Is b in W? How many vectors are in W?c. Show that a2 is in W. [Hint: Row operations are unnecessary.]a. Is b in {a₁, a₂, a3}? Select the correct choice below and, if necessary, fill in the answer box(es) to complete yourchoice.A. No, b is not in (a₁, a2, aç} since b is not equal to a₁, a2, or a3.B. Yes, b is in (a₁, a2, a3} since b = a(Type a whole number.)C. Yes, b is in {a₁, a2, a3} since, although b is not equal to a₁, a2, or a3, it can be expressed as a linearcombination of them. In particular, b = (a₁ + a₂ + ([ аз.(Simplify your answers.)D. No, b is not in {a₁, a2, a3} since it cannot be generated by a linear combination of a₁, №₂, and аз.

Answered: Image /qna-images/answer/7f6f698b-05d7-4d13-9a0c-e62f8fd1ba86.jpg

Let u = 6 - 1 and v= 6 Show that a a -[:] k Let b = k How can it be shown that a vector b is in Span {u, v}? is in Span {u, v} for all a and k. A. Determine if the system containing u, v, and b is consistent. If the system is consistent, then b is in Span {u, v}. B. Determine if the system containing u, v, and b is consistent. If the system is consistent, b might be in Span {u, v}. C. Determine if the system containing u, v, and b is consistent. If the system is consistent, then b is not in Span {u, v}. D. Determine if the system containing u, v, and b is consistent. If the system is inconsistent, then b is in Span {u, v}. Find the augmented matrix [uv b]

Let u = 6 - 1 and v= 6 Show that a a -[:] k Let b = k How can it be shown that a vector b is in Span {u, v}? is in Span {u, v} for all a and k. A. Determine if the system containing u, v, and b is consistent. If the system is consistent, then b is in Span {u, v}. B. Determine if the system containing u, v, and b is consistent. If the system is consistent, b might be in Span {u, v}. C. Determine if the system containing u, v, and b is consistent. If the system is consistent, then b is not in Span {u, v}. D. Determine if the system containing u, v, and b is consistent. If the system is inconsistent, then b is in Span {u, v}. Find the augmented matrix [uv b]

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter8: Applications Of Trigonometry

Section8.4: The Dot Product

Problem 46E

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