MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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In AC, there is only one element namely 23, because rest of the members in set A (17,19,20,21,25) do not belong to the set C, and hence there is only one common element among A and C sets.
Now, Bc has elements which are in S but not in B, so:
Bc = {3,6,9,10,11,12,16,17,18,19,20,23,24}
Now, Bc contains 23 too.
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