= Let Σ {0,1}. Let C₁ be the language of all strings that contain a 1 in their middle third. Let C₂ be the language of all strings that contain two is in their middle third. So C₁ = {xyz| x, z E Σ and y = "1", where |x| = |z≥ |y|} and C₂ = {xyz|x, z EE" and y E *10*10*, where |x| = |z||y|}. a. Show that C₁ is a CFL. b. Show that C2 is not a CFL.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Would you be able to help me with question 2.48 and its associated components? I'm struggling with this specific problem and would really appreciate your guidance since I'm not certain about the necessary steps. If feasible, could you specify which section pertains to part A and part B in your explanation, and provide calculations for both parts? Your assistance would be greatly valued.

Can you label the parts so I know which part is part A and which one is part B.

Σ
2.48 Let = {0,1}. Let C₁ be the language of all strings that contain a 1 in their
middle third. Let C₂ be the language of all strings that contain two 1s in their
middle third. So C₁ = {xyz| x, ze Σ and y Є "1", where |x| = z≥y}
and C₂ = {xyz|x, z EE" and y EΣ*10*10*, where |x| = |||y|}.
a. Show that C₁ is a CFL.
b. Show that C2 is not a CFL.
Transcribed Image Text:Σ 2.48 Let = {0,1}. Let C₁ be the language of all strings that contain a 1 in their middle third. Let C₂ be the language of all strings that contain two 1s in their middle third. So C₁ = {xyz| x, ze Σ and y Є "1", where |x| = z≥y} and C₂ = {xyz|x, z EE" and y EΣ*10*10*, where |x| = |||y|}. a. Show that C₁ is a CFL. b. Show that C2 is not a CFL.
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