Let H(x) = "x plays hockey". Let B(x)= " plays basketball". Which statement below means "No one who plays hockey also plays basketball"? OVx (-H(x)^-B(x)) OVx-(H(x) v B(x)) OVx-(H(x)→ B(x)) Ox-(H(x) ^ B(x)) O-3x (H(x) ^ B(x))

Let H(x) = "x plays hockey". Let B(x)= " plays basketball". Which statement below means "No one who plays hockey also plays basketball"? OVx (-H(x)^-B(x)) OVx-(H(x) v B(x)) OVx-(H(x)→ B(x)) Ox-(H(x) ^ B(x)) O-3x (H(x) ^ B(x))

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Let H(x) = "x plays hockey".
Let B(x)= " plays basketball".
Which statement below means "No one who plays hockey also plays basketball"?
OVx (-H(x) A-B(x))
OVx-(H(x) v B(x))
OVx-(H(x)→ B(x))
Ox-(H(x) ^ B(x))
O¬3x (H(x) ^ B(x))

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Let H(x)= " plays hockey". Let B(x) = "x plays basketball". Which statement below means "There is someone who plays hockey and someone who plays basketball"? OVx (H(x) ^ B(x)) Ox (H(x) ^ B(x)) OVx (H(x) V B(x)) OVx (H(x)→ B(x)) 3x (H(x) v B(x)) xH(x)^3x B(x) OVx (B(x) → H(x))
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