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Let H= [] : 7x² + 8y² ≤1 scalar-to show that H is not a subspace of R2. H is not a subspace of R2 because the two vectors 1 0 √√8 (Use a comma to separate vectors as needed.) H is not a subspace of R2 because the scalar 4 and the vector which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a 1 0 √7 show that H is not closed under addition. show that H is not closed under scalar multiplication.

Let H= [] : 7x² + 8y² ≤1 scalar-to show that H is not a subspace of R2. H is not a subspace of R2 because the two vectors 1 0 √√8 (Use a comma to separate vectors as needed.) H is not a subspace of R2 because the scalar 4 and the vector which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a 1 0 √7 show that H is not closed under addition. show that H is not closed under scalar multiplication.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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ܪܘ question which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a 1 0 √7 show that H is not closed under addition. show that H is not closed under scalar multiplication. Let H= 0 : 7x² + 8y² scalar-to show that H is not a subspace of R². H is not a subspace of R2 because the two vectors 0 (Use a comma to separate vectors as needed.) H is not a subspace of R2 because the scalar 4 and the vector √√8 18
Transcribed Image Text:ܪܘ question which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a 1 0 √7 show that H is not closed under addition. show that H is not closed under scalar multiplication. Let H= 0 : 7x² + 8y² scalar-to show that H is not a subspace of R². H is not a subspace of R2 because the two vectors 0 (Use a comma to separate vectors as needed.) H is not a subspace of R2 because the scalar 4 and the vector √√8 18
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