Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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### Finding the x-Intercepts of a Quadratic Function

Given the quadratic function:
\[ f(x) = x^2 + 4x + 1 \]

We aim to find the x-intercepts of the graph of \( y = f(x) \).

#### Step-by-Step Solution:

To find the x-intercepts, we set \( y = 0 \) and solve for \( x \):
\[ f(x) = 0 \]
\[ x^2 + 4x + 1 = 0 \]

This quadratic equation can be solved using the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

For the equation \( x^2 + 4x + 1 = 0 \), the coefficients are:
- \( a = 1 \)
- \( b = 4 \)
- \( c = 1 \)

Substitute these values into the quadratic formula:
\[ x = \frac{-4 \pm \sqrt{4^2 - 4 \cdot 1 \cdot 1}}{2 \cdot 1} \]
\[ x = \frac{-4 \pm \sqrt{16 - 4}}{2} \]
\[ x = \frac{-4 \pm \sqrt{12}}{2} \]
\[ x = \frac{-4 \pm 2\sqrt{3}}{2} \]
\[ x = -2 \pm \sqrt{3} \]

Therefore, the x-intercepts are at:
\[ x = -2 + \sqrt{3} \]
\[ x = -2 - \sqrt{3} \]

On the provided interface, the options presented for selecting the x-intercepts are:
- A textbox for entering the x-intercepts.
- An option for selecting "No solution" if no real x-intercepts exist.

In this case, there are real solutions, and they should be entered in the textbox if available or selected appropriately.
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Transcribed Image Text:### Finding the x-Intercepts of a Quadratic Function Given the quadratic function: \[ f(x) = x^2 + 4x + 1 \] We aim to find the x-intercepts of the graph of \( y = f(x) \). #### Step-by-Step Solution: To find the x-intercepts, we set \( y = 0 \) and solve for \( x \): \[ f(x) = 0 \] \[ x^2 + 4x + 1 = 0 \] This quadratic equation can be solved using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] For the equation \( x^2 + 4x + 1 = 0 \), the coefficients are: - \( a = 1 \) - \( b = 4 \) - \( c = 1 \) Substitute these values into the quadratic formula: \[ x = \frac{-4 \pm \sqrt{4^2 - 4 \cdot 1 \cdot 1}}{2 \cdot 1} \] \[ x = \frac{-4 \pm \sqrt{16 - 4}}{2} \] \[ x = \frac{-4 \pm \sqrt{12}}{2} \] \[ x = \frac{-4 \pm 2\sqrt{3}}{2} \] \[ x = -2 \pm \sqrt{3} \] Therefore, the x-intercepts are at: \[ x = -2 + \sqrt{3} \] \[ x = -2 - \sqrt{3} \] On the provided interface, the options presented for selecting the x-intercepts are: - A textbox for entering the x-intercepts. - An option for selecting "No solution" if no real x-intercepts exist. In this case, there are real solutions, and they should be entered in the textbox if available or selected appropriately.
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